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The enthalpy change of fusion (ΔH_fus) represents the amount of energy required to melt a unit mass of a solid at its melting point. To calculate the total energy needed to melt a specific mass of solid, you can use the formula: ( Q = m \times ΔH_fus ), where ( Q ) is the total energy, ( m ) is the mass of the solid, and ( ΔH_fus ) is the enthalpy of fusion. By multiplying the mass by the enthalpy of fusion, you obtain the total energy required for the phase change from solid to liquid.
If an object is rolling without slipping, then its kinetic energy can be expressed as the sum of the translational kinetic energy of its center of mass plus the rotational kinetic energy about the center of mass. The angular velocity is of course related to the linear velocity of the center of mass, so the energy can be expressed in terms of either of them as the problem dictates, such as in the rolling of an object down an incline. Note that the moment of inertia used must be the moment of inertia about the center of mass. If it is known about some other axis, then theparallel axis theorem may be used to obtain the needed moment of inertia.
Sphere radius, R = (28 cm)/2 = 14 cm = 0.14 m Speed, v = 2 m/s Mass, M = 2.5 kg Rotational KE = ½𝙸𝜔² For solid sphere, the moment of inertia, 𝙸 = ⅖MR² Rotational KE = ½(⅖MR²)(v/R)² = ⅕Mv² = ⅕(2.5 kg)(2 m/s)² = 2 J Total KE = Linear KE + Rot KE Total KE = ½Mv² + ⅕Mv² Total KE = (7/10)(Mv²) Total KE = (7/10)(2.5 kg)(2 m/s)² Total KE = 7 J Angular momentum, 𝜔 = v/R = (2 m/s)/(0.14 m) = 14.3 rad/s
The delta Hfusion, or enthalpy of fusion, is the amount of energy required to convert a unit mass of a solid into a liquid at its melting point without changing its temperature. To calculate the energy needed to melt a specific mass of solid, you multiply the mass of the solid by the delta Hfusion value. The formula is: Energy = mass × ΔHfusion. This gives the total energy required to completely melt the given mass of the substance.
The total potential energy of all microscopic particles in an object is due to the interatomic forces between them, which can be significant in solid and liquid states. The total kinetic energy of the particles is associated with their random motion, which increases with temperature. Both potential and kinetic energies contribute to the overall internal energy of the object.
The enthalpy change of fusion (ΔH_fus) represents the amount of energy required to melt a unit mass of a solid at its melting point. To calculate the total energy needed to melt a specific mass of solid, you can use the formula: ( Q = m \times ΔH_fus ), where ( Q ) is the total energy, ( m ) is the mass of the solid, and ( ΔH_fus ) is the enthalpy of fusion. By multiplying the mass by the enthalpy of fusion, you obtain the total energy required for the phase change from solid to liquid.
The kinetic energy of a rolling ball is the energy it possesses due to its motion. It is calculated using the formula KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the ball, and v is the velocity of the ball. When a ball is rolling, it has both translational and rotational kinetic energy, which can be calculated separately and then added together to find the total kinetic energy of the ball.
It is conserved. The potential energy of the ball sitting at the top of the hill is converted into kinetic energy of the rolling ball.
If an object is rolling without slipping, then its kinetic energy can be expressed as the sum of the translational kinetic energy of its center of mass plus the rotational kinetic energy about the center of mass. The angular velocity is of course related to the linear velocity of the center of mass, so the energy can be expressed in terms of either of them as the problem dictates, such as in the rolling of an object down an incline. Note that the moment of inertia used must be the moment of inertia about the center of mass. If it is known about some other axis, then theparallel axis theorem may be used to obtain the needed moment of inertia.
Sphere radius, R = (28 cm)/2 = 14 cm = 0.14 m Speed, v = 2 m/s Mass, M = 2.5 kg Rotational KE = ½𝙸𝜔² For solid sphere, the moment of inertia, 𝙸 = ⅖MR² Rotational KE = ½(⅖MR²)(v/R)² = ⅕Mv² = ⅕(2.5 kg)(2 m/s)² = 2 J Total KE = Linear KE + Rot KE Total KE = ½Mv² + ⅕Mv² Total KE = (7/10)(Mv²) Total KE = (7/10)(2.5 kg)(2 m/s)² Total KE = 7 J Angular momentum, 𝜔 = v/R = (2 m/s)/(0.14 m) = 14.3 rad/s
The amount of charge on the sphere is the total electric charge present on the surface of the sphere.
The answer depends on the specifics of the question. The idea though, is that when they are in equilibrium, both the solid and the liquid should have the same amount of energy PER MOLECULE. The fact that there is a solid component and a liquid component means that either the solid is melting or the liquid is freezing. In most situations, that means that the temperature of the whole mixture is constant. Another idea is that the energy in the molecules can either be kinetic or potential energy. Basically, the more kinetic energy PER MOLECULE an object has, the higher the object's temperature. Furthermore, the more potential energy PER MOLECULE that the object has, the further apart the molecules are from each other. Combining these ideas, here are a few possible answers to your question. 1. There is more solid than liquid. On average, the solid's molecules have the same kinetic energy as the liquid. The solid, having more molecules, has more kinetic energy total. The liquid has more potential energy in total. The solid has more overall energy. 2. There is more liquid than solid. On average, the liquid's molecules have the same kinetic energy as the solid. The liquid, having more molecules, has more kinetic energy total. The liquid also has more potential energy in total. The liquid has more overall energy. 3. There are equal amounts of liquid and solid. On average, the liquid's molecules have the same kinetic energy as the solid. The liquid has equal kinetic energy as the solid due to the even split. The liquid also has more potential energy in total. The liquid has more overall energy. These three are the main possibilities, and as can be seen in the details, the answer depends on the relative amounts of liquid and solid.
The total surface area of a sphere when the radius is 4 equals 201.1 units2
The energy is radiated equally in all directions into a sphere with a radius of 150 million kilometres, which has a surface area. On that sphere sits the Earth with a radius of 6378 kilometres, which has a circular cross-section area which intercepts part of the total energy. The ratio of the two areas answers the question.
A spectacular landmark in the history of mathematics was the discovery by Archimedes (287-212 B.C.) that the volume of a solid sphere is two- thirds the volume of the smallest cylinder that surrounds it, and that the surface area of the sphere is also two-thirds the total surface area of the same cylinder.
more. in any case, going from a solid to a gas requires more energy than going from a solid to a liquid. Considering Hess's Law, break down the reaction into two parts; solid to liquid, and then liquid to gas. Total energy of sublimation of the substance will be the sum of the two reactions.
The formula for calculating the charge density of a sphere is Q / V, where is the charge density, Q is the total charge of the sphere, and V is the volume of the sphere.