Well, honey, IO2 doesn't exist. But if you meant IO2-, then you've got yourself a total of 18 valence electrons. I hope that clears things up for you, darling.
Yes, IO2 is polar. The molecule has an uneven distribution of electrons which gives rise to a permanent dipole moment, making it polar.
The central atom in the hypothetical iodite ion would be surrounded by 10 electrons
The bond angle for IO2 is around 120 degrees.
The formula for the iodite anion is IO2-
1. Io2. Europa3. Ganymede4. Callisto
The oxyanions of iodine include iodate (IO3-), iodite (IO2-), and hypoiodite (IO-). Each of these oxyanions contains a different number of oxygen atoms bonded to an iodine atom.
IO- is an ion, not a compound. it is called the hypoiodite ion.
The anion periodate - IO4 (from the periodic acid HIO4); the charge is -1.
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Reductant Iodide (I-) can be oxidised to other (more postive) oxidation numders by loosing electrons to the oxidant. Depending on the oxidant's strength this can change to the following numbers: 0 (zero) in I2 , and +1, +2, +3, +4 (in hypoiodite IO-, iodite IO2-, iodate IO3-, periodate IO4- respectively)
The electron pair geometry for the iodate ion (IO2) is trigonal planar. This is because the central iodine atom is surrounded by three areas of electron density: two bonding pairs from the iodine-oxygen bonds and one lone pair. The arrangement of these electron pairs minimizes repulsion, resulting in a trigonal planar shape.
The formula for cobalt(III) iodide is CoI3. It is composed of one cobalt ion with a +3 charge and three iodide ions with a -1 charge each, resulting in a neutral compound.