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The voltage of a galvanic cell made with nickel (Ni) typically ranges from about 0.5 to 0.7 volts, depending on the specific half-reactions and the concentrations of the solutions involved. In a common configuration, nickel can be paired with a more reactive metal like zinc or a non-metal like copper, which influences the overall cell potential. The exact voltage can be calculated using the Nernst equation based on the standard electrode potentials of the involved half-reactions.

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1d ago

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It depends on the voltage. Divide the watt-hours (Wh) by the voltage (V) and you will get the Ampere-hours (Ah). So if the voltage is at 10.8V, divide 47 Wh by 10.8V to get about 4.352 Ah. Finally, convert the Ah to milli-Ah (mAh) by multiplying by 1000 to get 4,352 mAh which is rounded to 4400 mAh. So 47 Wh at 10.8V is about 4400 mAh. -UnrivaledShogun.


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