To solve this problem, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for V, we get V = (nRT)/P. Plugging in the values given (n = 0.323 mol, T = 265 K, P = 0.900 atm, and R = 0.0821 L.atm/mol.K), we can calculate the volume of the gas.
419 mL
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
Using the ideal gas law, V = (nRT)/P, where V is volume, n is moles, R is the gas constant, T is temperature in Kelvin, and P is pressure, we can calculate the volume to be 7.34 L.
Chilling the sample in the Reid vapor pressure test helps to reduce the vapor pressure of the volatile components in the sample, making it easier to measure accurately. This allows for more precise determination of the vapor pressure under controlled conditions.
423mL
419 mL
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
If the pressure on a sample of gas is raised three times and the temperature is kept constant, according to Boyle's Law, the volume of the gas will decrease proportionally to maintain a constant temperature. This means the gas will be compressed and occupy a smaller volume.
More pressure means less volume. Calculate the ratio of pressure, then divide the 4.2 liters by that ratio.This assumes: * That the temperature doesn't change. * That the gas behaves like an ideal gas.
Using the ideal gas law, V = (nRT)/P, where V is volume, n is moles, R is the gas constant, T is temperature in Kelvin, and P is pressure, we can calculate the volume to be 7.34 L.
To find the new volume, you can use the combined gas law formula: (P1 * V1) / T1 = (P2 * V2) / T2. Since pressure is constant, it can be eliminated. Rearrange the formula to solve for V2: V2 = (V1 * T2) / T1. Plug in the values: V2 = (20 ml * 323 K) / 141 K = 45.1 ml. So, the sample of gas would occupy 45.1 ml at 50 C.
Chilling the sample in the Reid vapor pressure test helps to reduce the vapor pressure of the volatile components in the sample, making it easier to measure accurately. This allows for more precise determination of the vapor pressure under controlled conditions.
When the temperature of a sample of air increases, the partial pressure of oxygen also increases.
The sample of water that has the lowest vapor pressure is the sample at a lower temperature. Vapor pressure decreases as temperature decreases because fewer molecules have enough energy to escape into the gas phase.
multiply the mass and the density