5126 cm3
The volume of 10 grams of sugar depends on the density of the sugar. The volume can be calculated by dividing the mass by the density of the sugar. For example, if the density of sugar is 1.59 g/cm3, then the volume of 10 grams of sugar would be approximately 6.29 cm3.
Yes, the volume of a gas at Standard Temperature and Pressure (STP) can be calculated from the number of molecules using the ideal gas law. At STP (0°C and 1 atm), one mole of an ideal gas occupies 22.4 liters. Since Avogadro's number (approximately (6.022 \times 10^{23}) molecules) defines one mole, you can convert the number of molecules to moles and then multiply by 22.4 liters to find the volume at STP.
The amount of dirt in 10 grams is simply 10 grams, as grams measure weight, not volume or quantity. The density of the dirt may vary depending on its composition and moisture content, but weight remains constant at 10 grams regardless.
mass = density x volume Mass = 5 grams per centimeter cubed x 10 centimeters cubed = 50 grams
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
The mass is 10 727 kg.
10 grams of calcium carbide can produce approximately 4.4 liters of acetylene gas at standard conditions (STP). This is calculated based on the stoichiometry of the reaction between calcium carbide and water to produce acetylene gas.
At STP, water is a liquid with a density of 1000.000 grams per liter. The gram molecular mass of water is 18.01528. Therefore, the number of moles of water in one liter is 1000.000/18.01528 or 55.5084 moles. The number of molecules in one liter is therefore 55.5084 X 6.022 X 1023 or about 3.34272 X 1025, and the volume of one molecule is therefore 1 [exact]/3.34272 X 1025 or 2.99158 X 10-24 liter.
The volume of 10 grams of sugar depends on the density of the sugar. The volume can be calculated by dividing the mass by the density of the sugar. For example, if the density of sugar is 1.59 g/cm3, then the volume of 10 grams of sugar would be approximately 6.29 cm3.
10 ml
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
0.01 kg
You need to apply the equation pV = nRT p = Pressure (1x10^5 Pa at STP) n = Number of moles (1.51x10^24 / 6.02x10^24) T = Temperature (273 K at STP) R = Universal gas constant (8.31) This gives the volume as 0.005 m^3
To find the number of atoms in 110 grams of CO2, you first need to determine the number of moles by dividing the mass by the molar mass of CO2 (44.01 g/mol). Next, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, there are approximately 2.5 x 10^24 atoms in 110 grams of CO2.
10 ml of water has 10 c.c. volume