mL is a unit of volume !
To find the volume of the alloy, use the formula for density: Density = Mass / Volume. First, calculate the volume of water displaced by the alloy when immersed: Volume of water displaced = Mass in air - Mass in water. Then, use the density of water (1g/cm^3) to find the volume, as the volume of water displaced equals the volume of the alloy. Finally, calculate the density of the alloy by dividing its mass by the volume obtained.
The volume of gold displacing the water can be found using the density formula: density = mass/volume. Rearranging the formula to solve for volume, volume = mass/density. Plugging in the values given, volume = 100 grams / 19.3 grams per ml = 5.18 ml. So, the gold should displace 5.18 ml of water.
Density = Mass / Volume Density = 45grams/5ml = 9g/ml
To calculate the volume of water displaced by 1.82 g of cobalt, we need to know the density of cobalt which is 8.9 g/mL. Using the formula density = mass/volume, we can rearrange it to volume = mass/density. Thus, the volume of water displaced by 1.82 g of cobalt would be 0.204 mL.
Can't answer this because you have given the mass, but not the volume. Density = mass / volume.
Since the density (mass divided by volume) of water is about 1.0 g/mL the volume of 6.5 gram is6.5(g) / 1.0(g/mL) = 6.5 mL
The formula for density is density = mass/volume. In this case, the mass is 25 g and the volume is 25 ml. Therefore, the density of water in this scenario would be 1 g/ml.
water is not measure in unit of mass but in volume for it is a liquid and liquid is measure in volume. confusing
Only if it is water, which has a mass of 1gram per ml volume
To find the volume of the alloy, use the formula for density: Density = Mass / Volume. First, calculate the volume of water displaced by the alloy when immersed: Volume of water displaced = Mass in air - Mass in water. Then, use the density of water (1g/cm^3) to find the volume, as the volume of water displaced equals the volume of the alloy. Finally, calculate the density of the alloy by dividing its mass by the volume obtained.
No, mL are a unit of volume and grams are a unit of mass. 1 mL of water has a mass of 1 g
The volume of the object is the difference in water level before and after the object is added, which is 10 ml (30 ml - 20 ml). The density of the object is mass divided by volume, so 2g / 10 ml = 0.2 g/ml. Therefore, the density of the object is 0.2 g/ml.
The volume of gold displacing the water can be found using the density formula: density = mass/volume. Rearranging the formula to solve for volume, volume = mass/density. Plugging in the values given, volume = 100 grams / 19.3 grams per ml = 5.18 ml. So, the gold should displace 5.18 ml of water.
Density = mass devided by volume (gram per millilittre)52.9 (g) / [39.3 (ml) - 15.0 (ml)] =52.9 (g) / 24.3 (ml) =2.17 g/mlBy the way, there is no such pure metal with this density:Aluminum: 2.7 g/ml and Beryllium: 1.85 g/ml and only Si in between! (Si 2.33 g/ml, nonmetal)
The volume of the stopper can be calculated by subtracting the initial volume of the water from the final volume. In this case, the volume of the rubber stopper would be 30.9 ml - 25 ml = 5.9 ml. Now, divide the mass of the rubber stopper (8.46 g) by its volume (5.9 ml) to find its density. Density = Mass/Volume, so the density of the rubber stopper would be 8.46g / 5.9ml = 1.43 g/ml.
You have answered this question for yourself. The Density is 0.94 g/mL However, do you mean , 'what is the rocks volume?' Remember the eq'n density = mass./ volume. Algebraically rearranged volume = mass / density Hence volume = 20g/ 0.94 g/mL volume = 2.276 mL
Density = Mass / Volume Density = 45grams/5ml = 9g/ml