Whatever someone will pay for it! /\/\/\
what a jerk, didnt even help you out.
if this is in deed the Delta Match H-Bar Rifle from 1987 should be worth $1,500usd
The heisenberg uncertainty principle is what you are thinking of. However, the relation you asked about does not exist. Most formalisms claim it as (uncertainty of position)(uncertainty of momentum) >= hbar/2. There is a somewhat more obscure and less useful relation (uncertainty of time)(uncertainty of energy) >= hbar/2. But in this relation the term of uncertainty of time is not so straightforward (but it does have an interesting meaning).
A quantum state is exactly as it sounds. It is the state in which a system is prepared. For example, one could say they have a system of particles and at time, t=(some number), the particles are at position qi (qi is a generalized coordinate) and have a momentum, p=(some number). You then know the state of the system. There are other properties that can be know for a particle. You could create a system of particles with a particular angular momentum or spin, etcetera. - A quantum fluctuation arises from Heisenberg's uncertainty principle which is \delta E times \delta t is greater than or equal to \hbar and it is defined as the temporary change in the amount of energy in a point of space. This temporary change of energy only happens on a small time scale and leads to a break in energy conservation which then leads to the creation of what are called virtual particles.
Associated with each measurable parameter in a physical system is a quantum mechanical operator. Now although not explicitly a time operator the Hamiltonian operator generates the time evolution of the wavefunction in the form H*(Psi)=i*hbar(d/dt)*(Psi), where Psi is a function of both space and time. Also I don't believe that in the formulation of quantum mechanics (QM) time appears as a parameter, not as a dynamical variable. Also, if time were an operator what would be the eigenvalues and eigenvectors of such an operator? Note:A dynamical time operator has been proposed in relativistic quantum mechanics. A paper I found on the topic is; Zhi-Yong Wang and Cai-Dong Xiong , "Relativistic free-motion time-of-arrival", J. Phys. A: Math. Theor. 40 1987 - 1905(2007)
There are two parts to this. First is, "What is the physical significance of a wave function?" Secondly, "Why do we normalize it?"To address the first:In the Wave Formulation of quantum mechanics the wave function describes the state of a system by way of probabilities. Within a wave function all 'knowable' (observable) information is contained, (e.g. position (x), momentum (p), energy (E), ...). Connected to each observable there is a corresponding operator [for momentum: p=-i(hbar)(d/dx)]. When the operator operates onto the wave function it extracts the desired information from it. This information is called the eigenvalue of the observable... This can get lengthy so I'll just leave it there. For more information I suggest reading David Griffith's "Introduction to Quantum Mechanics". A math knowledge of Calculus II should suffice.To address the second:Normalization is simply a tool such that since the probability of finding a particle in the range of +/- (infinity) is 100% then by normalizing the wave function we get rid of the terms that muddy up the answer the probability.An un-normalized wave function is perfectly fine. It has only been adopted by convention to normalize a wave function.ex. un-normalized wave function (psi is defined as my wave function)- The integral from minus infinity to positive infinity of |psi|^2 dx = 2piex. normalized wavefunction- The integral from minus infinity to positive infinity of |psi|^2 dx = 1
There are two parts to this. First is, "What is the physical significance of a wave function?" Secondly, "Why do we normalize it?"To address the first:In the Wave Formulation of quantum mechanics the wave function describes the state of a system by way of probabilities. Within a wave function all 'knowable' (observable) information is contained, (e.g. position (x), momentum (p), energy (E), ...). Connected to each observable there is a corresponding operator [for momentum: p=-i(hbar)(d/dx)]. When the operator operates onto the wave function it extracts the desired information from it. This information is called the eigenvalue of the observable... This can get lengthy so I'll just leave it there. For more information I suggest reading David Griffith's "Introduction to Quantum Mechanics". A math knowledge of Calculus II should suffice.To address the second:Normalization is simply a tool such that since the probability of finding a particle in the range of +/- (infinity) is 100% then by normalizing the wave function we get rid of the terms that muddy up the answer the probability.An un-normalized wave function is perfectly fine. It has only been adopted by convention to normalize a wave function.ex. un-normalized wave function (psi is defined as my wave function)- The integral from minus infinity to positive infinity of |psi|^2 dx = 2piex. normalized wavefunction- The integral from minus infinity to positive infinity of |psi|^2 dx = 1
Call Colt's Manufacturing Company
Customer Solutions
 at800-962-2658 and they will tell you.
You will have to call Colt to find out.
You will have to call Colt. Sn goes beyond published data.
No way to answer without the entire serial number. You can call Colt and they will tell you.
Model 6601
100-1000 usd
Any of the on line auction sites, gun shop, gun show, Shotgun News.
Fiind a copy of "The Black Rifle", both volumes. You can research it then.
100-1000 USD or so
Yes
600-1200
500-800 depending on what "very good" turns out to be.