What isotope is formed when 28P emits a positron?

Answer 1

In this reaction we see an isotope of phosphorus,28P, undergo beta plus decay. In beta plus decay, a proton in the nucleus of an atom undergoes a transformation wherein an up quark becomes a down quark. This event, mediated by the weak nuclear force (or weak interaction), results in the proton becoming a neutron. When this happens, the atom changes from one element to another element in a process called transmutation. Here we see phosphorus become silicon, and the equation might look like this: 1528P => 1428Si + e+ + ve In this beta plus decay event, we see the phosphorus-28 atom transforming into a silicon-28 atom, and we see the positron (e+) and the neutrino (ve) kicked out of the nucleus on the back side of the event. Some links are provided below for extra investigation.

Answer 2

When 28P emits a positron (β+ particle), it transforms into 28Si (silicon-28) through the process of beta-plus decay. This isotope is stable and is commonly found in nature.