What mass of CuO will be obatined by heating 12.5gm of copper carbonate?

Answer 1

12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)

0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)

= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO

Answer 2

To find the mass of CuO produced, first calculate the molar mass of CuO and CuCO3. Then, use the stoichiometry of the chemical reaction between CuCO3 and CuO to determine the amount of CuO produced from 12.5g of CuCO3. Finally, calculate the mass of CuO using the molar mass and the amount determined in the previous step.