What mass of chromium is in a 283-kg quantity of chromium(III) carbonate?

Answer 1

To find the mass of chromium in 283 kg of chromium(III) carbonate (Cr2(CO3)3), we first determine the molar mass of the compound. The molar mass of chromium(III) carbonate is approximately 194.19 g/mol, which contains 2 chromium atoms (about 52.00 g/mol each). Thus, the total mass of chromium in the compound is about 104.00 g/mol.

Using the proportion of chromium in the compound, the mass of chromium in 283 kg of chromium(III) carbonate can be calculated as follows:

[ \text{Mass of chromium} = \left(\frac{104.00 \text{ g/mol}}{194.19 \text{ g/mol}}\right) \times 283,000 \text{ g} \approx 147,000 \text{ g} \text{ or } 147 \text{ kg}. ]

Therefore, there are approximately 147 kg of chromium in 283 kg of chromium(III) carbonate.