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To find the number of nitrogen atoms in 5.00 g of magnesium nitride (Mg₃N₂), first calculate the molar mass of Mg₃N₂, which is approximately 100.95 g/mol (24.31 g/mol for Mg and 14.01 g/mol for N). The number of moles in 5.00 g of Mg₃N₂ is about 0.0495 moles. Since each formula unit of Mg₃N₂ contains 2 nitrogen atoms, the total number of nitrogen atoms is calculated as: 0.0495 moles × 2 × 6.022 × 10²³ atoms/mole, which equals approximately 5.95 × 10²² nitrogen atoms.

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