What pressure must be used to compress 850 mL of argon gas at 146 kPa to 150 mL Temperature is held constant?

Answer 1

What pressure must be used to compress 850 mL of argon gas at 146 kPa to 150 mL? (Temperature is held constant.)

Answer 2

The initial and final volumes of the gas are related by Boyle's Law: (P_1V_1 = P_2V_2). Therefore, the pressure needed to compress 850 mL of argon gas at 146 kPa to 150 mL, with temperature constant, is calculated as follows: (P_2 = \frac{P_1V_1}{V_2} = \frac{146 \text{ kPa} \times 850 \text{ mL}}{150 \text{ mL}} = 825.33) kPa. Thus, a pressure of approximately 825.33 kPa is required for compression.