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To determine the quantity of limestone (calcium carbonate, CaCO₃) needed to produce 56 kg of calcium oxide (CaO), we use the decomposition reaction:

[ \text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2 ]

The molar mass of CaO is approximately 56 g/mol, and the molar mass of CaCO₃ is about 100 g/mol. Therefore, from the stoichiometry of the reaction, 100 g of CaCO₃ produces 56 g of CaO. To find the amount of limestone required for 56 kg of CaO, we calculate:

[ \text{Required CaCO}_3 = \frac{100 , \text{g}}{56 , \text{g}} \times 56000 , \text{g} \approx 100000 , \text{g} \text{ or } 100 , \text{kg} ]

Thus, 100 kg of limestone will yield 56 kg of CaO.

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1d ago

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