The formula you are looking for is (amperage when kilowatts are shown). 1 MW = 1000 kW.
I = kW x 1000/ 1.73 x E x pf. 1000 x 1000 = 1000000/1.73 x 11000 x .90 = 1000000/17127 = 58.38 amps.
The minimum separation for a voltage of 34.5kV and conductor spans of 50 meters or less is 600 mm. The vertical clearance is 6.7 meters . For countries that never changed to the metric system 50 meters is about 150 feet and 600 mm is about 24 inches, 6.7 meters is about 22 feet. The minimum separation for a voltage of 15 kV and conductor spans of 50 meters or less is 400 mm. The vertical clearance is 6.1 meters.
Fully loaded - 2.62 amps at 11kV. The no load depends on the transformer design, but it will usually be significantly less than the full load amps (not sure on this size, but on larger transformers it is typically ~.05 - .1% full load, so you'd be looking at ~2.5 mA RMS). The connection type is not important. Transformers are very efficient, thus there is not a whole lot of loss in the "average" transformer. The actual loss will depend on the design criteria of the transformer.
Determine the type you need (primary voltage, secondary voltage, power rating in volt amperes - not watts, size, etc.) then check a catalog at an electrical or electronics parts store for a standard transformer meeting your requirements. If you find one and the store stocks it, buy it; if not have them order it for you.If there is no standard transformer meeting your requirements, one would have to have a company that custom winds transformers design and build it for you. Unless you would be buying in quantity, this will be expensive.
1.8A is the current or I. the time is 1 second, or t. and you don't know the charge or Q. the formular is I=Q/t so you substitute the values into the equation. so 1.8=Q/1 then rearrange, so Q=1.8*1 so Q=1.8. then you need to divide the charge by the charge of one electron which is -1.6E-19(E is expotential so X10) so 1.8/-1.6E-19=-1.125E19 and the unit is mms-1 so the answer would be -1.125E19mms-1 i hope that is helpful =D
It depends on the design of the transformer but 1 MVA is a common size for an 11 kV / 415 v three-phase transformer.
6350.8 volts AC rms. The phase to earth voltage is ( square root(3) ) x lower than the phase-phase voltage on a 3 phase system.
for USA, Canada and other countries running a 60 Hz supply service.A 11kV single phase line is one phase of a three phase system. The three phase system voltage is found by multiplying 11kV x 1.73. The three phase primary system voltage is 19kV. A transformer with a 11 kV primary can have a secondary of 115/230 depending on the internal connections in the transformer's case.For the UK11 kV is the standard three-phase h.v. distribution voltage in the UK, where it is a line voltage (i.e. it is the voltage measured between any pair of the three line conductors). A single-phase distribution transformer is connected between any two lines, so 'single-phase 11-kV' is simply a connection made between any two lines of an 11-kV three-phase system.As the primary windings of three-phase 11-kV distribution transformers are delta (3-wire) connected, the primary phase voltage is numerically equal to the primary line voltage (11 kV).
Regulation =(Obtained voltage per phase - rated voltage per phase)/rated voltage per phase *100
500Mw at 11kv works out to 45000 aa bit big for any wire manufactured on this planetsuggest you go to a more practical voltage like 132,000VAnswerSince we are inevitably talking about a three-phase transformer, the line current is determined fromIL= rated apparent power / (1.732 x UL) = (500 x 106) / 1.732 x 11 x 103)...which works out at 26 244 A which, as the original answer suggests, is not a practical value for this combination.
Because the tranformer calculation for ratings is calculated with the formfactor which is 1.11 constant. Regards Mithin kudva
Because if we use a generator of 33kv or higher then the radii must be of 2-3 meters that is not good. And also the area of the generator will be very high and losses and heat paameters will also be high. The main point is that we use 11kv generator at power plants and we have to step up the power to 220KV or 500KV etc. So we use 11kv or 22kv instead of 33 kv or higher.. By doing so we save the cost of area required, radii of rotor, and losses produced by higher power generators.
Possibly... but only a trained electrical technician would be licensed to do that kind of work!
I think, you are talking about a 11/33KV Transformer and by mistyping same has become 1133KV. However, rating shall be on the basis of 18MW +Loading factor . A 25/31.5MVA rating shall take care of of all these.
If one of the phases continuously takes a high load with a poor power factor it might have tripped a circuit breaker in the capacitor bank.
The minimum separation for a voltage of 34.5kV and conductor spans of 50 meters or less is 600 mm. The vertical clearance is 6.7 meters . For countries that never changed to the metric system 50 meters is about 150 feet and 600 mm is about 24 inches, 6.7 meters is about 22 feet. The minimum separation for a voltage of 15 kV and conductor spans of 50 meters or less is 400 mm. The vertical clearance is 6.1 meters.
600mm is the distance between two conductors in 11kv line