The combustion of methane (CH₄) is an exothermic reaction that releases energy when it reacts with oxygen (O₂) to form carbon dioxide (CO₂) and water (H₂O). The standard enthalpy change of combustion for methane is approximately -802 kJ/mol, indicating that this amount of energy is released per mole of methane combusted. This value can be determined through calorimetry experiments or referenced from thermodynamic tables.
The reaction that shows the formation of carbon dioxide (CO2) releasing 393.5 kJ/mol is the combustion of carbon in oxygen, represented by the balanced equation: C(s) + O2(g) → CO2(g). This exothermic reaction indicates that when one mole of carbon reacts with oxygen to form carbon dioxide, it releases 393.5 kJ of energy. This energy release is a key factor in various applications, including combustion engines and the generation of heat in industrial processes.
The reaction that shows the formation of CO2 releasing 393.5 kJ/mol is typically represented as the combustion of carbon or hydrocarbons. For example, the reaction for the combustion of carbon can be written as: [ C(s) + O_2(g) \rightarrow CO_2(g) ] This reaction indicates that the formation of one mole of carbon dioxide from solid carbon and oxygen gas releases 393.5 kJ of energy, demonstrating an exothermic process.
The reaction that shows the formation of CO2 releasing 393.5 kJ/mol is the combustion of carbon, represented as: [ C(s) + O_2(g) \rightarrow CO_2(g) ] In this exothermic reaction, when one mole of carbon reacts with oxygen to form carbon dioxide, it releases 393.5 kJ of energy, indicating that the formation of CO2 is energetically favorable.
10,267 kJ are needed
To calculate the energy generated from freezing 2.5 g of water, we use the heat of fusion (Hfusion) of water, which is 6.03 kJ/mol. First, convert the mass of water to moles: (2.5 , \text{g} \div 18.02 , \text{g/mol} \approx 0.1386 , \text{mol}). Then, multiply the number of moles by the heat of fusion: (0.1386 , \text{mol} \times 6.03 , \text{kJ/mol} \approx 0.835 , \text{kJ}). Thus, approximately 0.835 kJ of energy is released when 2.5 g of water freezes.
The enthalpy of combustion is determined by calorimetry.
The reaction that shows the formation of carbon dioxide (CO2) releasing 393.5 kJ/mol is the combustion of carbon in oxygen, represented by the balanced equation: C(s) + O2(g) → CO2(g). This exothermic reaction indicates that when one mole of carbon reacts with oxygen to form carbon dioxide, it releases 393.5 kJ of energy. This energy release is a key factor in various applications, including combustion engines and the generation of heat in industrial processes.
The significant jump in ionization energy from the first to the second indicates the removal of an electron from a filled energy level. This suggests the atom is in the second group of the periodic table, since elements in this group have a filled outer s sublevel before starting to fill the p sublevel in the subsequent period.
The reaction that shows the formation of CO2 releasing 393.5 kJ/mol is typically represented as the combustion of carbon or hydrocarbons. For example, the reaction for the combustion of carbon can be written as: [ C(s) + O_2(g) \rightarrow CO_2(g) ] This reaction indicates that the formation of one mole of carbon dioxide from solid carbon and oxygen gas releases 393.5 kJ of energy, demonstrating an exothermic process.
Energy profile A
The enthalpy change for forming sodium chloride from its elements can be calculated using the equation: Enthalpy change = Ionization energy of sodium + Electron affinity of chlorine. Plugging in the values, we get: 496 kJ/mol + (-349 kJ/mol) = 147 kJ/mol. Therefore, the enthalpy change for forming sodium chloride is 147 kJ/mol.
10,267 kJ are needed
To calculate the energy generated from freezing 2.5 g of water, we use the heat of fusion (Hfusion) of water, which is 6.03 kJ/mol. First, convert the mass of water to moles: (2.5 , \text{g} \div 18.02 , \text{g/mol} \approx 0.1386 , \text{mol}). Then, multiply the number of moles by the heat of fusion: (0.1386 , \text{mol} \times 6.03 , \text{kJ/mol} \approx 0.835 , \text{kJ}). Thus, approximately 0.835 kJ of energy is released when 2.5 g of water freezes.
Brainly says it’s energy profile B for APEX please correct if i’m wrong.
it can never be spontanious
it is never spontaneous
It is not spontaneous.