To determine the size of the breaker needed for a 9,000-watt broiler operating at 220 volts, you can use the formula: Amperage (A) = Watts (W) / Volts (V). In this case, 9,000 W / 220 V = approximately 40.91 A. It's common practice to add a safety margin, so a 50-amp breaker would be appropriate to handle the load safely.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
To determine the amperage for 9000 watts, you need to know the voltage at which the power is being consumed. The formula to calculate amperage is Amps = Watts / Volts. For example, if the voltage is 120V (typical for household circuits in the US), the amperage would be 9000 watts / 120 volts = 75 amps. However, if the voltage is different, such as 240V, then the amperage would be 9000 watts / 240 volts = 37.5 amps.
9000 BTU/hour is equivalent to 2300 watts so the heater will draw 10 amps on 230 volts.
P=EI. MEANS POWER EQUALS VOLTAGE TIME AMPERAGE .9 X 3.7 = 3.33 WATTS. 3.33 WATTS FOR ONE HOUR AT 3.7 volts
If it is a portable generator the breaker should be self contained within the generators panel. If the generator is a stationary standby unit a voltage has to be stated to calculate the conductor size and hence the breaker size to protect the conductor. Amps = Watts/Volts.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
The burners will most likely be 240V. By keeping the range at 240 volts it will use less amps that at 120V. Say a range and oven is rated at 9000 watts. Watts = amps x volts. 9000/240V = 37.5 amps. 9000/120V = 75 amps. As you can see at 120 volts the amperage is double over 240 volts. You would need a 100 amp breaker and #4 wire to accomodate the range on 120 volts.
To determine the amperage for 9000 watts, you need to know the voltage at which the power is being consumed. The formula to calculate amperage is Amps = Watts / Volts. For example, if the voltage is 120V (typical for household circuits in the US), the amperage would be 9000 watts / 120 volts = 75 amps. However, if the voltage is different, such as 240V, then the amperage would be 9000 watts / 240 volts = 37.5 amps.
9000 BTU/hour is equivalent to 2300 watts so the heater will draw 10 amps on 230 volts.
If your generator is rated at 1000 watts continuous......and you are using 120V.....available amps are 1000/120 =8.3 .
The relationship between amps (electrical current, or I), volts (electrical potential, or V) and watts(electrical power, or P) is represented by the equation P=VI. So at 110 volts, a 9000 watt generator can provide a maximum of about 82 amps.
P=EI. MEANS POWER EQUALS VOLTAGE TIME AMPERAGE .9 X 3.7 = 3.33 WATTS. 3.33 WATTS FOR ONE HOUR AT 3.7 volts
1055 watts = 1 BTU/s, so 9000 watts x 1 BTU/s/W x 3600s/hr = 30,710BTUH, or about 2 1/2 tons.
Divide the wattage rating on the tag by the voltage it uses and that will give you the amperage.
A 1 hp electric motor draws ABOUT 746 watts. Multiply volts times amps to get watts. a 1/2 hp motor will use about 3.1 amps @ 120 volts. A 12 hp motor is a VERY large motor, and will draw 8900-9000 watts of power (and use 220-440 volt power)
if I am informed correctly; it outputs OVER 9000 DECIBLES OF SOUND!!!!! 9000 THAT'S IMPOSSIBLE -NAPPA
If it is a portable generator the breaker should be self contained within the generators panel. If the generator is a stationary standby unit a voltage has to be stated to calculate the conductor size and hence the breaker size to protect the conductor. Amps = Watts/Volts.