To determine the volume of M AgNI required to precipitate all of the platinum (Pt) in a solution, you need to know the concentration of Pt in the solution and the stoichiometry of the reaction between AgNI and Pt. Assuming you have the molarity of Pt and its molar mass, you can calculate the moles of Pt present. Then, using the 1:1 molar ratio of AgNI to Pt, you can find the required volume of AgNI by dividing the moles of AgNI needed by its molarity. Without specific values, I cannot provide an exact volume.
When the volume of a solution containing ions bound together as a solid is reduced, the concentration of the ions in the solution increases. If the solution becomes supersaturated, some ions may begin to precipitate out of the solution, forming solid particles. This process can lead to the formation of new solid phases or the growth of existing solid crystals, depending on the specific ions and conditions of the solution.
When the volume of a solution containing dissolved ions is reduced, the concentration of those ions increases as they remain bound together in the solid lattice structure. If the volume is reduced significantly, the increased concentration may lead to supersaturation, potentially causing the ions to precipitate out of solution and form a solid. Additionally, if the temperature rises due to the volume reduction, it can further influence the solubility and behavior of the ions in the solution.
The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
This depends on the desired pH, volume of solution, initial pH, etc.
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
You cannot make a solution of AgCl, it is an insoluble salt
To precipitate all the chloride ions in solution, you would need a 1:1 ratio of Ag+ to Cl-. The molar ratio between silver nitrate (AgNO3) and chloride ions (Cl-) is 1:1. So, you would need the same volume of 0.20 M AgNO3 solution as the volume of the chloride ions solution to precipitate all the Cl-.
When the volume of a solution containing ions bound together as a solid is reduced, the concentration of the ions in the solution increases. If the solution becomes supersaturated, some ions may begin to precipitate out of the solution, forming solid particles. This process can lead to the formation of new solid phases or the growth of existing solid crystals, depending on the specific ions and conditions of the solution.
When the volume of a solution containing dissolved ions is reduced, the concentration of those ions increases as they remain bound together in the solid lattice structure. If the volume is reduced significantly, the increased concentration may lead to supersaturation, potentially causing the ions to precipitate out of solution and form a solid. Additionally, if the temperature rises due to the volume reduction, it can further influence the solubility and behavior of the ions in the solution.
add barium chloride or barium nitrate to a solution containing sulphate ions SO4 2-. To the same solution add hydrochloric acid in excess. OBSERVATIONS, a white precipitate which is insoluble in excess acid confirms presence of SO42- IF IT DISSOLVES then it confirms SO32- ----------------------------------------- 1) Add barium nitrate solution under acidic conditions (use an equal volume of hydrochloric acid) to the unknown solution 2) A white precipitate of barium sulphate forms if sulphate ions are present
The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
43.28 M
To determine the volume needed to achieve a specific molarity in a solution, you can use the formula: volume (amount of substance) / (molarity). This formula helps calculate the volume of the solution needed to reach the desired concentration.
This depends on the desired pH, volume of solution, initial pH, etc.
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
Foulger's reagent is a solution used in analytical chemistry to test for the presence of zinc ions. It consists of a mixture of potassium ferrocyanide and potassium ferricyanide. When added to a solution containing zinc ions, a green precipitate forms, indicating the presence of zinc.
To find the volume of the solution containing 0.500 g of NaCl, first, calculate the moles of NaCl using its molar mass (58.44 g/mol). Then use the molarity formula (Molarity = moles/volume) to find the volume. The volume of a 0.150 M solution that contains 0.500 g of NaCl would be approximately 8.5 ml.