1:2
It has a charge of 2-, S2-
Cu + 2NaOH ---> Cu(OH)2 + 2NaSince we have a finite amount of two reactants we must first determine which is the limiting reactant. For Cu: n= m/M = 0.500 g/63.53 g/mol = 7.87E-3 mol For NaOH: n = CV = (3.0 mol/L)(0.0300 L) = 9.00E-2 mol Copper is by far the limiting reactant therefore we will use its amount to find the maximum Cu(OH)2 that can be yielded from the reaction. Since the above reaction scheme indicates that Cu and Cu(OH)2 are in a 1 to 1 ratio, their molar amounts are the same ie. at the end of the reaction there will be 7.87E-3 mol of Cu(OH)2 To find the mass that corresponds to this molar amount we multiply by the molar mass of Cu(OH)2 (97.56 g/mol): m=nM = (7.87E-3 mol)(97.56 g/mol) = 0.7678 g Therefore 0.500 g of Cu will yield 0.768 g (3 sig fig) of Cu(OH)2.
For the molecular balance of the equation it would be: CuSO4 (aq) + Na2S (aq) = CuS (s) + Na2SO4 (aq). For the net ionic balance of the equation it would be: Cu2+ (aq) + S2(aq) = CuS (s).
The formula for aqueous copper nitrate is Cu(NO3)2.
The noble gas that is isoelectronic with S2- is Argon. Both S2- and Argon have 18 electrons.
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
The oxidation number tells you the "combining power" of that element. For example, if Cu has a 1+ oxidation number then it will combine with Cl in a 1:1 ratio, and result in CuCl. If Cu has an oxidation number of 2+, then it will combine with Cl in a 1:2 ratio, and result in CuCl2.
Copper(I) sulfate is Cu2SO4: the ratio Cu/SO4 is 2.
The correct formula when Mg2+ and S2- react is MgS. Magnesium (Mg) has a 2+ charge, while sulfur (S) has a 2- charge, so they combine in a 1:1 ratio to form magnesium sulfide (MgS).
The formula for the ionic compound formed from lead (Pb2+) and sulfur (S2-) ions is PbS, with a 1:1 ratio of cations to anions. Lead has a 2+ charge while sulfur has a 2- charge, so they combine in a 1:1 ratio to form a neutral compound.
Simple whole number ratio implies that ratio of the elements in a compound is a whole number i.e. the ratio of elements bear whole number. For example in Cu2O, Cu and O combine in a simple whole number ratio of 2:1.
It generally refers to Copper(II) nitrate: Cu(NO3)2
The balanced equation for the reaction is: Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag Calculate the molar mass of Cu and Ag (Cu = 63.55 g/mol, Ag = 107.87 g/mol). Using the molar ratio of Cu to Ag (1:2), convert the mass of Cu to moles, then use the molar ratio to find the moles of Ag produced. Finally, convert moles of Ag to grams using the molar mass of Ag to find the grams of silver produced.
It has a charge of 2-, S2-
8:1
Given: a square with side = s and a circle with radius = s (radius is equal to the length of the side of the square) Areasquare = side squared = s2 Areacircle = pi times the square of the radius = pi times s2 Areasquare : areacircle = s2 : pi s2 = 1 : pi (The ratio is one to pi.)
Cu + HNO3 = Cu(NO3)2 + NO + H2O