It boils
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.
The boiling point of chloroform is 61,15 oC.
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
1 cal/gdegC x 225g x (100 - 50.5)degC heat to the boiling point 540 cal/g x 225g heat to vaporize the water 0.5 cal/gdegC x 225 g x (133-100)degC heat to chang temp of steam = 11137.5 cal + 121500 cal + 3712.5 cal = 14850 cal
The mass of undissolved potassium nitrate is cca. 3 g.
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.
Water is transformed in vapors.
The boiling point of chloroform is 61,15 oC.
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
The statement that is true is that tar in container A (100 °C) and container B (200 °C) is at a higher temperature than the tar in containers C (50 °C) and D (25 °C). Therefore, the tar in containers A and B is likely to be less viscous and flow more easily compared to the thicker, cooler tar in containers C and D.
1 cal/gdegC x 225g x (100 - 50.5)degC heat to the boiling point 540 cal/g x 225g heat to vaporize the water 0.5 cal/gdegC x 225 g x (133-100)degC heat to chang temp of steam = 11137.5 cal + 121500 cal + 3712.5 cal = 14850 cal
419.1 Joules are required to heat one gram of liquid water from 0.01 degC to 100 deg C. So the answer is 419.1*46 = 19278.6
The mass of undissolved potassium nitrate is cca. 3 g.
Yes, assuming we are talking about pure water and pure ice. Ice is the solid state of water and occurs at 32 degF or 0 degC.
A temperature change of 100 K is equivalent to a change of 100 degrees Celsius. This is because the size of a degree Celsius and a Kelvin is the same, but the zero point is different (0 K is absolute zero while 0°C is the freezing point of water).
Yes. It takes more time for hot water to freeze - the cooling process takes longer when you start from a higher temperature. Different liquids freeze at different temperatures. It depends how cold the place where you're putting the boiling water is, how much boiling water there is, etc. I think that each liquid has a specific temperature at which it freezes - it may not be associated with thickness.
At 60°C, about 31.6 g of copper (II) sulfate will dissolve in 100 g of water. This means that about 3.4 g of copper (II) sulfate will not dissolve and will form a saturated solution.