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What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
A solution prepared by dissolving 110 g of HC2H3O2 in 1.25 L total solution has a molarity of 1.47 M True or False?
True. To calculate the molarity, you need to divide the moles of solute by the volume of solution in liters. First, convert 110 g of HC2H3O2 to moles using its molar mass. Then, divide the moles by 1.25 L to get the molarity, which in this case is 1.47 M.
What is the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L?
To find the molarity, we first need to calculate the number of moles of NaI using its molar mass (149.89 g/mol). Then, we divide the moles of NaI by the volume of the solution in liters (0.250 L). This gives us the molarity, which would be around 1.43 M.
What is the molarity of a solution prepared by dissolving 0.31g of HNO3 in 300ml of water?
To find the molarity, first calculate the number of moles of HNO3: 0.31g / 63g/mol (molar mass of HNO3) = 0.0049 mol Then, convert 300ml to liters: 300ml/1000 = 0.3 L Finally, molarity = moles/volume = 0.0049 mol / 0.3 L = 0.0163 M
What will be the molarity for a solution prepared by dissolving a 10 grams compound with a molecular mass of 100 in 1 L of water?
The first step is to calculate the number of moles of the compound using the formula: moles = mass / molar mass. In this case, moles = 10 g / 100 g/mol = 0.1 moles. The molarity is then calculated by dividing the number of moles by the volume of solution in liters, so the molarity is 0.1 moles / 1 L = 0.1 M.
What is the molarity of a solution made by dissolving 25 grams of Mg in excess NaOH solution?
The molarity of the solution is 0.5 M.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
A solution is prepared by dissolving 16.2 g of benzene in 282 g CCL4 find molarity of thesolution density of the solution is 0.92gml?
To find the molarity of the solution, first calculate the total mass of the solution by adding the mass of benzene and CCl4. Then, use the density of the solution to convert the mass to volume. Finally, calculate the molarity using the formula: Molarity = moles of solute / volume of solution in liters.
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
How is concentrated solution prepared?
You prepare a solution by dissolving a known mass of solute (often a solid) into a specific amount of a solvent. One of the most common ways to express the concentration of the solution is M or molarity, which is moles of solute per liter of solution.
A solution prepared by dissolving 110 g of HC2H3O2 in 1.25 L total solution has a molarity of 1.47 M True or False?
True. To calculate the molarity, you need to divide the moles of solute by the volume of solution in liters. First, convert 110 g of HC2H3O2 to moles using its molar mass. Then, divide the moles by 1.25 L to get the molarity, which in this case is 1.47 M.
How 0.1M NaOH form?
0.1 M NaOH is prepared by dissolving sodium hydroxide (NaOH) pellets or flakes in water to make a 0.1 molar solution. This means there are 0.1 moles of NaOH dissolved in 1 liter of water. The molarity of the solution is calculated using the formula: Molarity = moles of solute / liters of solution.
What is the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L?
To find the molarity, we first need to calculate the number of moles of NaI using its molar mass (149.89 g/mol). Then, we divide the moles of NaI by the volume of the solution in liters (0.250 L). This gives us the molarity, which would be around 1.43 M.
What is the molarity of a solution made by dissolving 23.4g of sodium sulphate in enough water to make up a 125ml solution?
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
What will be the molarity for a solution prepared by dissolving 50 grams of KOH in 700ml of water?
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
What is the molarity of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
How does a scientist make two solutions with same molarity?
By dissolving the same number of moles of each substance in the same volume of water
