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What is the ratio produced if Tt is crossed with tt?
The ratio produced if Tt is crossed with tt is 1:1 for the genotype and 1:1 for the phenotype. This is because all the offspring will inherit a recessive allele from the tt parent, resulting in all of them having the same genotype and phenotype.
In pea plants the gene for tallness (T) is dominant over the gene for shortness (t). A homozygous dominant pea plant is crossed with a heterozygous pea plant and 200 seeds are produced. Approximately?
When a homozygous dominant pea plant (TT) is crossed with a heterozygous pea plant (Tt), the possible genotypes of the offspring are TT and Tt. This results in a 1:1 ratio of tall (TT and Tt) to short (tt) plants. Therefore, out of 200 seeds produced, approximately 200 seeds will be tall plants (100 TT and 100 Tt) and 0 seeds will be short (tt).
What is ratio for PHenotypic ration TT Tt TT Tt?
The phenotypic ratio for the given genotypes (TT, Tt, TT, Tt) can be determined by identifying the traits represented by these genotypes. In this case, both TT and Tt result in the dominant phenotype, while there are no recessive phenotypes present. Thus, the phenotypic ratio is 4:0, indicating that all offspring display the dominant trait.
If a hybrid tall plant is crossed with a dwarf plant then how many tall plants would be expected?
When a hybrid tall plant (Tt) is crossed with a dwarf plant (tt), the offspring can be predicted using a Punnett square. The possible genotypes for the offspring would be Tt (tall) and tt (dwarf). This results in a 1:1 ratio, meaning that approximately 50% of the offspring are expected to be tall plants (Tt) and 50% will be dwarf plants (tt).
When Mendel crossed short tt pea plants with short pea plants the offspring were?
When Mendel crossed short tt pea plants (homozygous recessive) with short pea plants that were heterozygous for height (Tt), the offspring would display a phenotypic ratio of 1 short (tt) to 1 tall (Tt). This is because the short plants (tt) can only contribute recessive alleles, while the heterozygous plants (Tt) can contribute either a dominant (T) or a recessive (t) allele. Therefore, half of the offspring would be tall and half would be short.
What is the ratio produced if Tt is crossed with tt?
The ratio produced if Tt is crossed with tt is 1:1 for the genotype and 1:1 for the phenotype. This is because all the offspring will inherit a recessive allele from the tt parent, resulting in all of them having the same genotype and phenotype.
What is the ratio if TT and tt are crossed?
When a true-breeding tall plant (TT) is crossed with a true-breeding short plant (tt), all the offspring in the first generation (F1) will be heterozygous (Tt) and exhibit the tall phenotype, as tall (T) is dominant over short (t). Therefore, the phenotypic ratio of the offspring will be 100% tall. If these F1 plants are then crossed with each other (Tt x Tt), the resulting phenotypic ratio in the second generation (F2) will be 3 tall (TT or Tt) to 1 short (tt).
In pea plants the gene for tallness (T) is dominant over the gene for shortness (t). A homozygous dominant pea plant is crossed with a heterozygous pea plant and 200 seeds are produced. Approximately?
When a homozygous dominant pea plant (TT) is crossed with a heterozygous pea plant (Tt), the possible genotypes of the offspring are TT and Tt. This results in a 1:1 ratio of tall (TT and Tt) to short (tt) plants. Therefore, out of 200 seeds produced, approximately 200 seeds will be tall plants (100 TT and 100 Tt) and 0 seeds will be short (tt).
What is ratio for PHenotypic ration TT Tt TT Tt?
The phenotypic ratio for the given genotypes (TT, Tt, TT, Tt) can be determined by identifying the traits represented by these genotypes. In this case, both TT and Tt result in the dominant phenotype, while there are no recessive phenotypes present. Thus, the phenotypic ratio is 4:0, indicating that all offspring display the dominant trait.
If a hybrid tall plant is crossed with a dwarf plant then how many tall plants would be expected?
When a hybrid tall plant (Tt) is crossed with a dwarf plant (tt), the offspring can be predicted using a Punnett square. The possible genotypes for the offspring would be Tt (tall) and tt (dwarf). This results in a 1:1 ratio, meaning that approximately 50% of the offspring are expected to be tall plants (Tt) and 50% will be dwarf plants (tt).
When Mendel crossed short tt pea plants with short pea plants the offspring were?
When Mendel crossed short tt pea plants (homozygous recessive) with short pea plants that were heterozygous for height (Tt), the offspring would display a phenotypic ratio of 1 short (tt) to 1 tall (Tt). This is because the short plants (tt) can only contribute recessive alleles, while the heterozygous plants (Tt) can contribute either a dominant (T) or a recessive (t) allele. Therefore, half of the offspring would be tall and half would be short.
What is the phenotypic ratio for Genotype TT Tt Tt tt?
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
Can a genotype for gray bodied fly be determined?
yes becasue the color changes and it doset mean it's not almost exactly the same as a black or even a purple fly when its crossed with another fly you get (tt) (TT) (tT) AND (Tt)
What percentage of the F2 generation had the genotype tt?
In a typical monohybrid cross involving two heterozygous parents (Tt x Tt), the F2 generation would have a genotype ratio of 1:2:1 for TT, Tt, and tt respectively. This means that 25% of the F2 generation would have the genotype tt. Thus, the percentage of the F2 generation with the genotype tt is 25%.
What are the genotype a of the parents?
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
Why was 3 1 the ratio in Mendels F2 generation?
In Mendel's F2 generation, the 3:1 ratio observed for dominant to recessive traits arises from the segregation of alleles during gamete formation. When he crossed heterozygous parents (Tt), the resulting offspring can inherit combinations of alleles that produce three dominant phenotype offspring (TT or Tt) and one recessive phenotype offspring (tt). This reflects the principles of Mendelian inheritance, specifically the law of segregation, where each parent contributes one allele for a trait, leading to the 3:1 phenotypic ratio in the F2 generation.
In the P generation a tall plant is crossed with a short plant The probability that an F2 plant will be tall is?
75% there will be TT, Tt, Tt, and tt. tt is going to be short. This means that 3/4 will be tall. 3/4 is 75%
