Answer: 50% Tall : 50% Short
The ratio produced if Tt is crossed with tt is 1:1 for the genotype and 1:1 for the phenotype. This is because all the offspring will inherit a recessive allele from the tt parent, resulting in all of them having the same genotype and phenotype.
When a homozygous dominant pea plant (TT) is crossed with a heterozygous pea plant (Tt), the possible genotypes of the offspring are TT and Tt. This results in a 1:1 ratio of tall (TT and Tt) to short (tt) plants. Therefore, out of 200 seeds produced, approximately 200 seeds will be tall plants (100 TT and 100 Tt) and 0 seeds will be short (tt).
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
75% there will be TT, Tt, Tt, and tt. tt is going to be short. This means that 3/4 will be tall. 3/4 is 75%
Homozygous for tall is TT Homozygous for short is tt All F1 offspring from this cross are Tt which makes them genotypically heterozygous and phenotypically tall.
The ratio produced if Tt is crossed with tt is 1:1 for the genotype and 1:1 for the phenotype. This is because all the offspring will inherit a recessive allele from the tt parent, resulting in all of them having the same genotype and phenotype.
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
yes becasue the color changes and it doset mean it's not almost exactly the same as a black or even a purple fly when its crossed with another fly you get (tt) (TT) (tT) AND (Tt)
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
In Mendel's F2 generation, the 3:1 ratio observed for dominant to recessive traits arises from the segregation of alleles during gamete formation. When he crossed heterozygous parents (Tt), the resulting offspring can inherit combinations of alleles that produce three dominant phenotype offspring (TT or Tt) and one recessive phenotype offspring (tt). This reflects the principles of Mendelian inheritance, specifically the law of segregation, where each parent contributes one allele for a trait, leading to the 3:1 phenotypic ratio in the F2 generation.
75% there will be TT, Tt, Tt, and tt. tt is going to be short. This means that 3/4 will be tall. 3/4 is 75%
The Yamaha TT-R225 was produced for 5 years, from 1999-2004.
Tt, tt -- novanet :)
The possible offspring outcomes of this cross would be 50% Tt (heterozygous) and 50% tt (homozygous recessive).
A cross between members of the F1 generation (Tt x Tt), results in the genotypic ratio of 1TT:2Tt:1tt genotypes in the F2 generation. Because the tall allele is dominant, the phenotypic ratio would be 3 tall:1 short in the F2 generation.
In the offspring generation from crossing two pea plants with TT genotypes, all the offspring will have the genotype Tt. However, all of these offspring will be tall since the tall trait is dominant (T) over the short trait (t). Therefore, there will be no short tt plants in the new generation.
rather TT Tt tt