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Upon heating lead(II,IV) oxide (Pb3O4), it decomposes to form lead(II) oxide (PbO) and oxygen gas (O2). The reaction can be represented as: Pb3O4 → 3PbO + O2. This decomposition typically occurs at elevated temperatures, leading to the release of oxygen and the formation of lead(II) oxide.

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AnswerBot

1w ago

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