In theory, if a bullet dropped vertically at the same instant that a bullet is fired horizontally from a gun at the same height, they should both hit the ground at the same time.
This example is used to emphasize that that horizontal motion and vertical motion may be analysed separately since they occur independently of each other.
This is one of those things that works better in theory than in practice.
There is a caveat that is important if you consider doing this in the real world. The process is not happening in a vacuum. The aerodynamics of the bullet fired at high speed is tremendously important. In early gun design, this was not understood and bullets fired from guns were very inaccurate and went up or down or right or left in unpredictable ways. Modern guns stabilize the trajectory by putting a spin on the bullet. The result makes the bullet act like a gyroscope and then to remain pointed forward when it encounters small anomalies in the air and wind. So, the moving bullet is subjected to vertical forces and can not be expected to drop at the same rate as a bullet with no horizontal motion.
The principle of independent horizontal and vertical motion works better when illustrated by throwing and dropping heavy rocks. The principle is entirely correct, but there are more vertical forces involved than gravity with the bullets.
Gravity has an effect the instant the bullet leaves the barrel. The bullet starts to fall towards the earth at the same rate as the dropped bullet. However, (assuming the ground follows the curve of the earth, or you are shooting over water) the dropped bullet will hit the ground/water first. The reason is that the as the fired bullet falls the ground is receding away from it (the curve of the earth). The extreme example of this is: the bullet is fired fast enough that as it falls, the curve of the earth is 'falling' continuously away below it; we would say this bullet is now in orbit around the planet. However, if the ground you are shooting over is 'flat' (i.e. flat like a ruler, NOT following the curve of the earth) then: yes, the two bullets will hit the ground at the same time.
The bullet dropped .1612 meters. To solve this type of problem, first determine how much time it took the bullet to travel to the target. Since Velocity = Distance / Time, Time = Distance / Velocity. In this problem Time = (50 m) / (275 m/s) = .1818 seconds. Now use this time to figure out how far the bullet would have fallen due to gravity. You've probably seen this equation (or something like it) before: Δy = vo*t - 1/2 * g * t2. This equation means that to find how far the bullet fell you need to know how long it was falling, how fast it was falling at the very beginning, and what the acceleration due to gravity is. We already figured out how long the bullet was falling, we know that it wasn't falling at all at the very beginning, and gravity = 9.8 m/s2. This means that: t = .1818 vo = 0 g = 9.8 So plug that in to the previous equation: Δy = (0) * (.1818) - (1/2) * (9.8) * (.1818)2. Δy = - .1612, with the - sign meaning the bullet went down and not up into the air.
The first bullet point of the male (human):Generally, males are taller and have bigger upper body muscles than females.
Lightning tends to strike tall objects such as trees, buildings, or towers because they offer an easier path for the electrical discharge to reach the ground. However, lightning can strike the ground directly or move horizontally, so being the tallest object does not guarantee a strike.
Probably the heaviest
The bullet fired horizontally will hit the ground first, given that it has an initial horizontal velocity that keeps it moving forward from the moment it leaves the gun. On the other hand, the bullet dropped from the end of the barrel only has the force of gravity acting on it, causing it to fall vertically, which is slower than the horizontal motion of the fired bullet.
Please describe how you drop something 'horizontally'
A bullet fired parallel to the gound, over flat ground, and a bullet dropped at the same time from same height will hit the ground at a time so close to each other as to be the same.
Gravity has an effect the instant the bullet leaves the barrel. The bullet starts to fall towards the earth at the same rate as the dropped bullet. However, (assuming the ground follows the curve of the earth, or you are shooting over water) the dropped bullet will hit the ground/water first. The reason is that the as the fired bullet falls the ground is receding away from it (the curve of the earth). The extreme example of this is: the bullet is fired fast enough that as it falls, the curve of the earth is 'falling' continuously away below it; we would say this bullet is now in orbit around the planet. However, if the ground you are shooting over is 'flat' (i.e. flat like a ruler, NOT following the curve of the earth) then: yes, the two bullets will hit the ground at the same time.
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
They should reach the ground together, since their initial vertical speed is the same, namely zero.
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
A cannonball fired horizontally and one dropped from the height of the muzzle simultaneous with the shot will hit the ground at the same instant, provided only that the ground under the muzzle and the ground where the shot lands are at the same elevation, i.e. the shot was not fired off the edge of a cliff or into the side of a mountain. To solve this kind of problems, it often helps to separate the movement, or the speed, into vertical and horizontal components. In this case, the vertical component of the speed is the same.
Depends on which one is dropped first. If they are both dropped at the same time, they will both reach the ground at the same time.
If a gun was parallel with the earth and was fired and at that very instant someone standing by the barrel dropped a bullet from beside the barrel, both bullets would hit the ground at the same time. Bullets start falling the instant they leave the end of the gun barrel. That is why hunters hold their rifles at an upward angle. It looks like the bullet will shoot up into the sky. The bullet will follow a curved path toward its target.
as done in Galileo's experiment when he dropped a large rock and a feather from a tall tower both hit the ground at the same moment when dropped from the same height.