The acceleration of the ball (after it leaves the thrower's hand) is the acceleration due to gravity, g.1 The vertical velocity of the ball at its apex is zero. The horizontal velocity is constant throughout the ball's flight; it is whatever it was at the outset of its arc.2 ---------------- 1. The acceleration due to gravity, g, is -9.8 m/s2 or -32.2 ft/s2. 2. Ignoring the effects of air resistance, which tend to slow things down.
A rock has the same constant acceleration from the moment it leaves your hand until the moment it hits the ground. It doesn't matter whether you dropped it or threw it, or in what direction it left you. The acceleration is 9.8 meters (32.2 feet) per second2 directed downwards. That's the acceleration of gravity on earth. As you asked, let's say you tossed it straight upwards. A tiny instant before it reaches the exact top, it has a small upward speed. A tiny instant after it passes the exact top, it has a small downward speed. During that tiny space of time, its upward speed decreases and its downward speed increases. That's a downward acceleration in anybody's book.
The product of velocity and time yields distance travelled if the velocity is constant for the time in question. If velocity is not constant, one must first calculate the average velocity over a given time period before multiplying it by the time involved.
At the highest point, the rock's velocity is momentarily zero as it changes direction from going up to coming back down. At this point, the rock has the maximum potential energy, which is then converted into kinetic energy as it falls back towards the ground. The greatest potential energy occurs at the highest point of the rock's trajectory.
Its velocity just before it hits the floor is found from kinematic equations and acceleration due to gravity; V = SqRt{2gy) = SqRt{19.6} = 4.4 m/s . The velocity after 1 ms is zero. The average deacceleration is the velocity difference divided by the time during impact; a = (4.4 - 0 )/.001 = 4400 m/ss .
The net force acting on a ball thrown in the air with upward velocity is the force of gravity acting downwards. Gravity causes the ball to accelerate towards the ground. At the highest point of its trajectory, the net force is zero since the upward velocity is momentarily halted before the ball begins to fall back down.
At the highest point in its trajectory, the vertical velocity of a projectile is zero. This is because the projectile has reached its peak height and is momentarily at rest before starting to descend.
Just before it reaches the highest point, the vertical component of velocity is upward.Just after it passes the highest point, the vertical component of velocity is downward.There's no way you can change from an upward velocity to a downward velocity smoothlywithout velocity being zero at some instant. A.True.
At the highest point, the velocity of the ball is zero because it momentarily stops before falling back down. The acceleration of the ball at the highest point is equal to acceleration due to gravity, which is directed downward toward the center of the Earth and is approximately 9.81 m/s^2.
Vertical velocity decreases to zero at the highest point of an object's trajectory when it momentarily stops moving upward before falling back down due to gravitational pull.
The acceleration is the acceleration of gravity, downwards, or 9.8m/s/s (32 ft/s/s). When ball is thrown straight up it has an initial velocity that is decreasing because of gravity; at the highest point velocity is zero but acceleration is always constant at gravity rate.
Assuming that there is no velocity in the horizontal direction, then the velocity at that instant is zero.
The velocity of the ball at its highest point is 0 m/s. At the highest point of its trajectory, the ball's vertical velocity slows to 0 before changing direction and starting to fall back down due to the force of gravity.
At the top of its trajectory, the acceleration of the stone is equal to the acceleration due to gravity, which is approximately 9.81 m/s^2 directed downward. This is because at the highest point, the stone momentarily comes to a stop before it starts falling back down.
The ball has an instantaneous velocity of zero at the highest point of its trajectory. This is because at that point, the ball changes direction from going up to coming down, causing its velocity to momentarily be zero before increasing in the opposite direction.
No. Any object that was shot by gun, flung by slingshot, or thrown by hand, begins accelerating downward at the acceleration of gravity as soon as it leaves the propulsion system. Zero velocity is true at the top, but acceleration is constant throughout the trajectory ... 9.8 m/s downward.
The slowest point of a projectile's trajectory is at the peak of its curve, where its vertical velocity momentarily reaches zero before changing direction and accelerating back downwards due to the force of gravity.
The ball has the highest gravitational potential energy when it is at its highest point in the air, as that is when it has a velocity of zero and is up the highest.