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What would happen if the concentration of H plus ions were the same on both sides of membrane when the channel opened?
H+ ions would not flow.
What would happen if there were no H ion concentration difference when a channel opened?
H+ ions would flow out of the mitochondrion
What would happen to the rate of a reaction with rate law rate k(NO)2(H2) if the concentration of NO were halved?
If the concentration of NO is halved in a reaction with the rate law rate = k(NO)²(H₂), the rate of the reaction would decrease. Specifically, since the rate is proportional to the square of the concentration of NO, reducing its concentration by half would result in the rate being reduced to one-fourth of its original value, assuming the concentration of H₂ remains constant. Therefore, the new rate would be k(0.5NO)²(H₂) = k(0.25NO²)(H₂) = (1/4) × original rate.
How would the equilibrium concentration of H½O be affected by removing H½ from the mixture?
If you remove H½ from the mixture, the equilibrium will shift to the left to compensate for the loss, meaning more H½O will dissociate to reform some of the missing H½. This will increase the concentration of H½O in an attempt to restore equilibrium.
What will happen to a weak acid dissociation equilibrium if more reactants were added?
Concentration of products would increase in order to attain equilibrium in the system again.For example:H2CO3 --> H+ + HCO3-K= ([H+][žHCO3-])/([H2CO3])K is constant for this process, so if you increase the concentration of reactants (H2CO3), in order for K to stay the same, concentration of products (H+, HCO3-) would also have to increase.It's part of Le Chatelier's principle: "If a chemical system at equilibrium experiences a change in concentration, temperature, volume, or partial pressure, then the equilibrium shifts to counteract the imposed change and a new equilibrium is established."So, in your case, adding more reactant would cause equilibrium to shift to the right (toward products), and therefore, their concentration would increase so that new equilibrium could be established.
What would happen if there were H plus ion concentration difference when the channel opened?
H plus ions would not flow
What would happen if the concentration of H plus were the same on both sides of the membrane when the channel opened?
H+ ions would not flow.
What would happen if the concentration of H plus ions were the same on both sides of the membrane when the channel opened?
H+ ions would not flow.
What would happen if the concentration of H plus ions were the same on the both sides of the membrane when the channel opened?
H+ ions would not flow.
What would happen if the concentration of H plus ions were the same on both sides of membrane when the channel opened?
H+ ions would not flow.
What would happen if the concentration of H ions were the same on both sides of the membrane when the channel opened?
If the concentration of H ions were the same on both sides of the membrane when the channel opened, there would be no net movement of H ions across the membrane. This would lead to an equilibrium state where the concentration of H ions remains constant on both sides of the membrane.
What would happen if the concentration of H plus ion were higher inside the mitochondrion than outside the mitochondrion when the channel opened?
H+ ions would flow out of the mitochondrion.
What would happen if there were no H ion concentration difference when a channel opened?
H+ ions would flow out of the mitochondrion
What would happen to the rate of a reaction with rate law rate k(NO)2(H2) if the concentration of NO were halved?
If the concentration of NO is halved in a reaction with the rate law rate = k(NO)²(H₂), the rate of the reaction would decrease. Specifically, since the rate is proportional to the square of the concentration of NO, reducing its concentration by half would result in the rate being reduced to one-fourth of its original value, assuming the concentration of H₂ remains constant. Therefore, the new rate would be k(0.5NO)²(H₂) = k(0.25NO²)(H₂) = (1/4) × original rate.
What would happen if the concentration of H ions were higher inside the mitochondrion than outside the mitochondrian when the channel opened?
H+ ions would not flow.
What number on the pH scale would the very strong acid correspond to?
It depends more on concentration then on strength:pH = - log10[H+]in which [H+] is the concentration of free H+ ions.
What would happen if theRe were no H plus ion concentration difference when the channel open?
H plus ions would not flow
