I need answer for this question.
The Nucleus would be damaged. Apex
The combined weight of all particles in an atomic nucleus is typically less than the combined weight of the individual particles due to the binding energy that holds the nucleus together. This is described by Einstein's mass-energy equivalence principle, E=mc^2, where a small amount of mass is converted to energy to hold the nucleus together.
the nucleus would be damaged. according to apex. hope this helps.:)
The nucleus would be damaged.
Large molecules would be able to enter and damage the nucleus.
It is unclear exactly how a single neutron could be removed from a Uranium-236 nucleus to create a Uranium-235 nucleus. (It would probably prove quite difficult to do.) As to the energy required to do this, about all we can do is look at the binding energy of this nucleus. It turns out that the binding energy per nucleon in the U236 nucleus is about 7.6 MeV (million electron volts). This suggests that it would take a minimum of about 7.6 MeV to pluck that neutron from the U236 nucleus to create the U235 nucleus.
The binding energy of a nucleus can be calculated using the mass defect and the relationship E=mc^2, where E is the binding energy, m is the mass defect, and c is the speed of light. With a mass defect of 0.00084 u, the binding energy would be approximately 1.344 x 10^-11 J per nucleus.
No, binding energy cannot be negative. Binding energy is always a positive quantity that represents the energy required to hold a system together. If the binding energy were negative, it would imply that the system is in an unstable state.
The nucleus would be damaged.
Iron has a stable nucleus, the most common isotope has 26 protons and 30 neutrons (Fe56). Elements around this point in the periodic table, like iron and nickel, have the highest binding energy of any nuclei, so they do not experience fission. Fission only ocurs with heavy nuclei such as U235 and PU 239 and a few others in that area, and when they fission they split into two fragments of elements which have higher binding energy. In these cases the total mass of the fission fragments is less than the mass of the original nucleus, and this is where the nuclear energy comes from, by E = mc2
No. Not under normal conditions. It is true that protons within the nucleus attract each other due to the residual binding energy left over from the binding energy that holds quarks together to form protons and neutrons, but that force does not extend beyond the nucleus before the electromagnetic force, a repulsive force, would override the residual binding energy. In order to bind protons from different nuclei together, more formally, different nuclei together, you need nuclear fusion, and that requires high temperature and high pressure, first to ionize the atom and strip away the electron shells, and second to bring the nuclei close enough together that the residual binding energy can overcome the electromagnetic force.
Than all the cells the nucleus is holding together would die
The Nucleus would be damaged. Apex
The combined weight of all particles in an atomic nucleus is typically less than the combined weight of the individual particles due to the binding energy that holds the nucleus together. This is described by Einstein's mass-energy equivalence principle, E=mc^2, where a small amount of mass is converted to energy to hold the nucleus together.
The nucleus would be damaged.
To find the total binding energy Use this formula: B= (number of neutrons)(neutron mass)+ (number of protons)(proton mass) - (Atomic Mass of helium). Then to keep the units correct, multiply that entire expression by 931.5 MeV/u. This is the TOTAL binding energy, and the binding energy per nucleon can be found by dividing the number you calculate above by the total number of protons and neutrons.
the nucleus would be damaged. according to apex. hope this helps.:)