In order for a hydrogen atom to have a continuous spectrum, the oscillation would have to be incoherent. In other words, there would be no fixed or steady state oscillation. In addition, the change in state of the oscillator would have to be incoherent. We know that the energy that is radiated from a hydrogen atom is due to changes in the energy states of the atom. Therefore, each of the states that the atom would have to reach must be perfectly random. This would produce a nearly continuous spectrum over a certain range in frequencies or wavelengths.
In some text books on physical chemistry it is stated that if an electron followed the classical laws of mechanics it would continue to emit energy in the form of electromagnetic radiation until it fell to the nucleus. It is not sensible to consider the spectrum of emitted electromagnetic radiation because its wavelength is a function of the Schrodinger equation under the influence of the Hamilton operator. So my only have desecrate values. A classical picture of the atom would not obey the Schrodinger equation so there is no way of predicting the way it would emit energy.
A continuous spectrum is produced when white light passes through a prism or when hot gas is heated to incandescence. In either case the light is separated into its component colors based on their different wavelengths. All the colors of the visible spectrum from red to violet are present in the resulting continuous spectrum.When white light passes through a prism the individual wavelengths of light are bent at different angles separating the light into a spectrum. This is known as dispersion. The prism separates the wavelengths of light into visible colors with the shortest wavelength being the color red and the longest wavelength being the color violet.When hot gas is heated to incandescence the gas molecules become excited and emit light. The light produced is a continuous spectrum because all the wavelengths of visible light are present. The intensity of the emitted light varies with the wavelength with the shortest wavelength having the greatest intensity and the longest wavelength having the least intensity.
The EM spectrum may, in fact, not be continuous, but quantised wrt the frequency of the emitted photons that comprise the spectrum. This implies that the frequency of oscillation of the emitting quantum mechanical system is quantised. To establish beyond doubt the continuity, or otherwise of the EM spectrum would require the accutate measurement of the frequency of individual photons. Given the magnitude of Planck's Constant (~ 6.26 x 10^-34 Js) the Planck-Einstein-Schrodinger equation, E = hv shows that, for a single photon a measurable signal cannot be generated at low frequencies (~ a few Hz), whilst at high frequencies (~ a few GHz) any quantisation of the frequency of the photon would not be observable.
A low-density, high-temperature gas cloud would emit a continuous spectrum. This spectrum shows a broad range of wavelengths without any distinct lines, characteristic of thermal radiation emitted by hot objects.
That would be sound waves, or the audio spectrum.
Any incandescent source such as candle flame, sun, carbon arc lamp would give continuous spectrum. When the temperature is low then red and orange may be there. As temperature increases then spectrum would extend towards violet end
If an atom's electrons were not restricted to particular energy levels, its spectrum would likely appear as a continuous spectrum rather than discrete lines. This is because the energy levels of the electrons in the atom contribute to the specific wavelengths of light emitted or absorbed, and without these restrictions, the energy transitions would be continuous, resulting in a continuous spectrum.
A rainbow would display a classic continuous spectrum because it contains a full range of colors blended seamlessly together, whereas a neon light, fluorescent light, and glowing nebula would exhibit line or emission spectra with distinct lines of color instead of a continuous spread.
The type of spectrum observed would depend on the source of light. A continuous spectrum is produced by a hot, dense object like a solid, liquid, or dense gas. An emission spectrum is generated by a thin, hot gas, while an absorption spectrum is created by a cooler gas in front of a light source.
A metal would not be attracted to either water's hydrogens or oxygens because metals typically do not have a strong affinity for interacting with individual water molecules. Metals and water molecules generally do not have a strong enough interaction to cause attraction between them.
Neither, they would join the spectrum together and become violet.
In some text books on physical chemistry it is stated that if an electron followed the classical laws of mechanics it would continue to emit energy in the form of electromagnetic radiation until it fell to the nucleus. It is not sensible to consider the spectrum of emitted electromagnetic radiation because its wavelength is a function of the Schrodinger equation under the influence of the Hamilton operator. So my only have desecrate values. A classical picture of the atom would not obey the Schrodinger equation so there is no way of predicting the way it would emit energy.
It's a line spectrum because of the quantization of energy- meaning you only see energy with levels n=1,2,3.... One would never see the energy level n=2.8 for instance- that would be the case if it were continuous rather than a line spectrum.
a continuous spectrum with all colors blending together.
A continuous spectrum is produced when white light passes through a prism or when hot gas is heated to incandescence. In either case the light is separated into its component colors based on their different wavelengths. All the colors of the visible spectrum from red to violet are present in the resulting continuous spectrum.When white light passes through a prism the individual wavelengths of light are bent at different angles separating the light into a spectrum. This is known as dispersion. The prism separates the wavelengths of light into visible colors with the shortest wavelength being the color red and the longest wavelength being the color violet.When hot gas is heated to incandescence the gas molecules become excited and emit light. The light produced is a continuous spectrum because all the wavelengths of visible light are present. The intensity of the emitted light varies with the wavelength with the shortest wavelength having the greatest intensity and the longest wavelength having the least intensity.
The EM spectrum may, in fact, not be continuous, but quantised wrt the frequency of the emitted photons that comprise the spectrum. This implies that the frequency of oscillation of the emitting quantum mechanical system is quantised. To establish beyond doubt the continuity, or otherwise of the EM spectrum would require the accutate measurement of the frequency of individual photons. Given the magnitude of Planck's Constant (~ 6.26 x 10^-34 Js) the Planck-Einstein-Schrodinger equation, E = hv shows that, for a single photon a measurable signal cannot be generated at low frequencies (~ a few Hz), whilst at high frequencies (~ a few GHz) any quantisation of the frequency of the photon would not be observable.
A low-density, high-temperature gas cloud would emit a continuous spectrum. This spectrum shows a broad range of wavelengths without any distinct lines, characteristic of thermal radiation emitted by hot objects.