20 cu cm
In order to measure volume, one normally sees how much water it displaces. If the body floats, the water displaced will be equal to the weight of the body, not the volume. It will be necessary to force the body down so that it is totally submerged. If there is an anchor and chain below the surface, the water displaced when the body is attached and submerged will have the same volume as the body.
No, a body totally submerged in a liquid displaces a volume of water equal to its own volume. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the fluid displaced by that object.
Archimedes principle states that a floating body displaces its own weight of water. The density of the water is fixed so the volume displaced by a floating body is is the same for floating bodies of the same weight. The water level will still be delta h1 as the volume of the block is not relevant to the amount of water displaced.
First, measure the mass of the water in the bathtub using a scale. Next, immerse yourself completely in the water and measure the increase in water level using a measuring cup. This increase in volume of water displaced is equal to your body volume. Finally, apply Archimedes' principle which states that the buoyant force acting on an object is equal to the weight of the water displaced, to calculate your mass.
if you are talking about the same glass that had water in it and THEN froze, then my friend the weight is the same. Ofcourse this is correct only if while freezing, no water spilled out of the glass (because ice takes up more space than water.
The water displaced by the body is equal to its volume.
This statement is not correct. The weight of the water displaced by a body in it, is equal to the buoyancy force that the body will experience. In the case the body floats on the surface of water, the weight of the water displaced by the body is equal to the weight of the body.
When a body or object is immersed in water that its volume is equal to the water displaced.
The buoyant force acting on a body in water is directly proportional to the volume of water displaced by the body. This is known as Archimedes' principle. The greater the volume of water displaced, the greater the buoyant force exerted on the body.
In order to measure volume, one normally sees how much water it displaces. If the body floats, the water displaced will be equal to the weight of the body, not the volume. It will be necessary to force the body down so that it is totally submerged. If there is an anchor and chain below the surface, the water displaced when the body is attached and submerged will have the same volume as the body.
When a body or object is immersed in water that its volume is equal to the water displaced.
Greek scholar Archimedes
Archimedes took a bowl full of water of known volume and then dipped the irregular shape body. Amount of water fall down is measured and is the volume of that body.
The weight of the fluid displaced by a floating body is equal to the weight of the floating body itself. This is known as Archimedes' principle. The volume of fluid displaced by a floating body is equal to the volume of the part of the body that is submerged in the fluid.
They are equal.When a boat is floating on water it displaces water equal to its weight(Archimedes Principle). As the density of water is less than boat so water displaced is greater than volume of boat. When the boat sinks water displaced is equal to volume of boat. So less water is displaced in 2nd case and consequently water level goes down.Note - relation between volume(v) mass(m) and density(d) : d = m/v
No, a body totally submerged in a liquid displaces a volume of water equal to its own volume. This is known as Archimedes' principle, which states that the buoyant force acting on an object is equal to the weight of the fluid displaced by that object.
Use Archimedes' Principle: the buoyancy force of a submerged (or partially submerged) object is the weight of the volume of water that the object displaces. In other words, find the volume of the object that is under water, and multiply that by the density of water (1000 kg/cubic meter) and gravity (9.8 meter/sec/sec).