The answer is c., The mass number.
Check step 5 below.
Let's walk through balancing a nuclear equation involving beta decay. We are going to figure out a balanced equation for thorium-234
1. You will need to find the atomic number for thorium (234) and the chemical symbol (Th).
2. We know that this is undergoing beta decay, so one of the products will be decaying.
3. We now need to set up the equation. We are going to use the following
4. Let's now set up the equation:
5. We will now figure out the mass number (A) of the product. We will do this as follows:234=mass number of thorium
0=mass number of beta particle
234=A+0
234=A
6. We will now figure out the atomic number (Z) of the product. We will do this as follows:
90=Z+(-1) (complete this by subtracting -1 to each side of the equation)
90-(-1)=Z+(-1) - (-1)
91=Z
7. So far we have this:
8. Now, we need to figure out the product element (X). We do this by looking for the element that has an atomic number of 91. This is protactinium (Pa). So, the complete balanced equation will look like this:
You have balanced an equation using beta decay.
This isotope is transformed in another isotope of another element.
D. All of these change. In alpha decay, an isotope emits an alpha particle, which consists of two protons and two neutrons, leading to a decrease in the atomic number and mass number of the parent isotope. This results in the formation of a new element with a different name, atomic number, and mass number.
Beryllium-9 is a stable isotope.
B. The name of the element does not change during beta decay. The atomic number (Z) increases by one unit as a neutron is converted to a proton, while the mass number (A) remains the same.
This isotope is lead-206.
This isotope is transformed in another isotope of another element.
The half life of an isotope refers to the rate at which a radioactive isotope undergoes radioactive decay. Specifically, it is the amount of time it takes for half of a given sample of a radioactive isotope to decay.
D. All of these change. In alpha decay, an isotope emits an alpha particle, which consists of two protons and two neutrons, leading to a decrease in the atomic number and mass number of the parent isotope. This results in the formation of a new element with a different name, atomic number, and mass number.
Beryllium-9 is a stable isotope.
B. The name of the element does not change during beta decay. The atomic number (Z) increases by one unit as a neutron is converted to a proton, while the mass number (A) remains the same.
This isotope is lead-206.
Phosphorus-32 is the radioactive isotope that undergoes beta decay to produce sulfur-32. During beta decay, a neutron in the nucleus of phosphorus-32 is converted into a proton and an electron, resulting in the formation of sulfur-32.
nothing, but another isotope with the same atomic mass is formed
When 90Sr undergoes beta decay, it forms 90Y (Yttrium-90). In beta decay, a neutron is converted into a proton, and an electron (beta particle) and an antineutrino are emitted.
When uranium undergoes alpha decay, it emits an alpha particle (which is equivalent to a helium nucleus, ( ^4_2He )), resulting in a decrease of its atomic number by 2 and its mass number by 4. For example, if uranium-238 (( ^{238}{92}U )) undergoes alpha decay, it transforms into thorium-234 (( ^{234}{90}Th )). Thus, the notation for the thorium isotope produced is ( ^{234}_{90}Th ).
The decay chain for U-238 stops at lead because lead-206 is a stable isotope, meaning it does not undergo further radioactive decay. Once uranium-238 undergoes a series of alpha and beta decays, it eventually reaches a stable isotope of lead, which ends the decay chain.
The parent isotope is the original radioactive isotope that undergoes decay to form the daughter isotope. The daughter isotope is the stable isotope that is formed as a result of the radioactive decay of the parent isotope.