Water is the solvent.
When salt is added to water until no more can dissolve, the solution is called a saturated solution. This occurs when the maximum amount of solute (salt) has been dissolved in the solvent (water), and any additional salt will remain undissolved at the bottom of the beaker. The concentration of the dissolved salt is at its highest possible level under the given conditions.
Not completely sure what you're asking, but copper sulfate (CuSO4) will dissolve easily in water to form a cool-looking blue colored solution.(The term is dissolve).
The volume of the water in Beaker X will be 100cm3, as you are not adding any more water to the equation (50X+100Y is not 150Y or X, but 50X+100Y) The total volume of matter in Beaker X will be 150cm3, and if the beaker is labelled, the volume measure will indicate 150cm3 due to the displacement of water. But as the answer to your question, the volume of water in Beaker X must be 100cm3 even though visual indicators will not show this due to the displacement of water by marbles
You can see drink crystals at the bottom of a beaker with water because the crystals are insoluble or only partially soluble in water. When added to water, they do not dissolve completely, leading to visible solid particles settling at the bottom. This phenomenon occurs due to the limited interaction between the solute (drink crystals) and the solvent (water), preventing full dissolution.
Use really clean equipment. Heat some water in a beaker so that it will dissolve more solute. Dissolve all that it will hold, to make sure add excess. Decant the liquid into another beaker allow no crystals to be transferred to the new beaker. Allow to cool slowly. Do not agitate. The cool solution will be supersaturated.
When you dissolve salt into water, the salt is the solute while the water is the solvent.
Put them in a beaker. Add water to the mixture. Agitate to insure dissolution. Centrifuge the colloidal suspension. Pour off the water into a different beaker and heat to 100C. Salt will be in the beaker where water was after complete evaporation. Sand will be in the other after drying. Sand doesn't dissolve in water. Salts do.
Use really clean equipment. Heat some water in a beaker so that it will dissolve more solute. Dissolve all that it will hold, to make sure add excess. Decant the liquid into another beaker allow no crystals to be transferred to the new beaker. Allow to cool slowly. Do not agitate. The cool solution will be supersaturated.
The temperature will decrease
To dissolve a piece of rock sugar quickly in a beaker of water, first, crush the rock sugar into smaller pieces to increase its surface area. Next, stir the water vigorously to facilitate the interaction between the sugar and water molecules. Finally, use warm water instead of cold, as higher temperatures enhance the solubility of sugar, allowing it to dissolve more rapidly.
When salt is added to water until no more can dissolve, the solution is called a saturated solution. This occurs when the maximum amount of solute (salt) has been dissolved in the solvent (water), and any additional salt will remain undissolved at the bottom of the beaker. The concentration of the dissolved salt is at its highest possible level under the given conditions.
To dissolve powder in water you typically need a beaker or a glass container to hold the water, a stir rod or stirring device to help the powder dissolve, and a scale to accurately measure the amount of powder being added to the water. Heating equipment like a hot plate may also be needed if the powder requires heat to dissolve.
Not completely sure what you're asking, but copper sulfate (CuSO4) will dissolve easily in water to form a cool-looking blue colored solution.(The term is dissolve).
The water in the beaker evaporated or was poured out.
The temperature of the solution decreases
The volume of the water in Beaker X will be 100cm3, as you are not adding any more water to the equation (50X+100Y is not 150Y or X, but 50X+100Y) The total volume of matter in Beaker X will be 150cm3, and if the beaker is labelled, the volume measure will indicate 150cm3 due to the displacement of water. But as the answer to your question, the volume of water in Beaker X must be 100cm3 even though visual indicators will not show this due to the displacement of water by marbles
There are more particles in the beaker with a large amount of water compared to a beaker with a small amount of water, assuming the water is the only substance present. This is because the volume of water in the larger beaker contains more individual water molecules than the volume of water in the smaller beaker.