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In certain breeds of dogs deafness is due to a recessive allele (d) of a particular gene and normal hearing is due to its dominant allele (D). What percentage of the offspring of a normal heterozygous?

If a normal heterozygous dog (Dd) is crossed with another normal heterozygous dog (Dd), the Punnett square shows the possible genotypes of the offspring: DD, Dd, Dd, and dd. This results in 25% DD, 50% Dd, and 25% dd. Therefore, 25% of the offspring would be expected to be deaf (dd).


How do genetics represent h dominant and Recessive allele?

A dominant genotype is represented as DD or Dd but with many different letters. The DD is a homozygous dominant, while the Dd is the heterozygous dominant. Recessive is always represented as dd or rr or whatever letter you want to use. It is always homozygous recessive. There can never be a heterozygous recessive.


What does dd mm yyy?

"dd mm yyy" is an incomplete date format. It seems to be missing the actual numbers for the day, month, and year. Typically, it should be written as "dd/mm/yyyy" or "dd-mm-yyyy" to represent the actual date.


If a dog's genotype is Dd if it has a disease what genotype does another mate have to have in order for have of the puppies to not have a disease?

There is not really enough information in the question to answer it properly. You would need to know what trait the D and d stood for to give a proper answer.If the dog's genotype is Dd and it has the disease, this suggests that the disease is caused by a dominant allele. A healthy bitch would have the genotype dd and half of her pups would have the disease. There is no mate which would produce all heathly pups.If the dog is symptom free then the disease is caused by a recessive allele. In which case the dog should be matted with a dog with the genotype DD to have 100% symptom free pups. Mating Dd to Dd would give 75% symptom free pups and 25% sufferers. Mating the Dd dog to a dd dog would give 50% disease free pups and 50% sufferers.


What is the list of genotypic ratio for all possible offspring's for DDxdd?

To determine the genotypic ratio for the cross DD (homozygous dominant) and dd (homozygous recessive), we can set up a Punnett square. All offspring will inherit one dominant allele (D) from the DD parent and one recessive allele (d) from the dd parent, resulting in 100% Dd (heterozygous) offspring. Therefore, the genotypic ratio for the offspring is 100% Dd, or simply 1:0:0 for DD:Dd:dd.