Try a RV or camping outlet store.
A back pin tower G4 12V DC 6W High Power LED Bulb 360 Degree is equivalent to a G 4 20W halogen bulb.See related links below.
In ideal conditions, about 6W Amps x volts = watts 500ma = 1/2 amp (1000ma to 1a) 0.5 X 12V = 6W
The percent efficiency would be calculated by dividing the useful output by the total input energy and multiplying by 100. In this case, the useful output is 6W (light energy produced) and the total input is 60W (electricity consumed). Therefore, the efficiency would be (6/60) * 100 = 10%.
here we have 2 eqns 20R+6W+1B=200 R+W+B=100 Thus solve it by hit and trial method... Like the one answer is 5 Red Beads 1 White Beads 94 blue Beads satisfies the two eqns 5+1+94=100 20*5+6*1+1*94=200
A 6W LED bulb is equivalent to a 40W traditional incandescent bulb in terms of brightness.
A 6W LED bulb is equivalent in brightness to a traditional incandescent bulb of about 40-60 watts.
The equivalent incandescent wattage for a 6W LED bulb is approximately 40 watts.
A back pin tower G4 12V DC 6W High Power LED Bulb 360 Degree is equivalent to a G 4 20W halogen bulb.See related links below.
there are 60 seconds in a minute therefore you divide 360 by 60 and get 6w. 360/60=6 6w is the answer.
In ideal conditions, about 6W Amps x volts = watts 500ma = 1/2 amp (1000ma to 1a) 0.5 X 12V = 6W
The percent efficiency would be calculated by dividing the useful output by the total input energy and multiplying by 100. In this case, the useful output is 6W (light energy produced) and the total input is 60W (electricity consumed). Therefore, the efficiency would be (6/60) * 100 = 10%.
6x-6w = 0
7x-6w = 1
It depends on the value of w. w < 6 then 6w < 36 w = 6 then 6w = 36 and w > 6 then 6w >36
If you mean: 6w = 0.144 then w = 0.24
Yes,they will. But the bulbs won't be very bright: Current will flow through all the filaments. However, with 6 times the impedance the power in each bulb will be tiny, almost invisible. For example, a 12V 6W bulb has a resistance of 24 ohms. 6 of them will have a total resistance of 144 ohms (nominally, filament resistance changes with temperature). 12V divided by 144 ohms gives 83 mA current. Using P = I2R, each bulb will have (.083)2x24 W, or 1/6 W. In a very dark room you might see a faint orange glow, but not much more.