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A) NaClO4 ==> Na^+ + ClO4
B) CH3OH ==> CH3OH
C) C6H12O6 ==> C6H12O6
D) CaCl2 ==> Ca^2+ + 2Cl^-
E) NiSO4 ==> Ni^2+ + SO4^2-
Since (D) dissociates into THREE ions, it will be the best conductor of an electric current assuming all are present at the same concentrations.

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