The only thing I can think of is the size match between Cl and the B or Al; there's more likely to be an interaction between the vacant AO on Al than B and the Cl lone pairs because the AOs are better matched in energy and size, making the bonding interaction more favourable.
I might be talking rubbish but that's one theory anyway!
A.P.
because ch4 has an octett and bh3 not so it dimerises to b2h6
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
BH3 is non polar.Inter moleculer forces are much weaker Wander Voals forces.NH3 have hydrogen bonds among molecules.They are very strong comparing to Vander Woals forces.So NH3 have high boiling point.
BH3 has three electron pairs around the boron atom, resulting in a trigonal planar molecular geometry due to the repulsion between the electron pairs around the central atom. This geometry allows for the maximum separation between electron pairs, leading to a more stable molecule.
In the Lewis dot structure for BH3, there should be 3 bonds drawn. Each hydrogen atom forms a single covalent bond with the boron atom. Boron has three valence electrons, so it can form three bonds with the hydrogen atoms.
BH3. but the compound generally exists as its dimer B2H6.
BH is not stable, there is no compound by that formula. BH3 (boron hydride) generally exists as the dimer, B2H6, diborane.
The formula for boron chloride is BCl3. This compound consists of one boron atom bonded to three chlorine atoms.
The predicted boiling point for borane is 440,34 oc.
In chess notation, "Bh3" typically refers to moving the bishop to the h3 square, which is not a legal move. On the other hand, "bx3" refers to capturing a piece on the x3 square with a pawn or bishop, which is a valid move. The "b" in "bx3" signifies the piece making the capture, while "x3" indicates the square of the captured piece.
The increasing acidity order of these Lewis acids is: BCl3 < BBr3 < BI3 < BF3. This trend is due to the decreasing ability of the halogen to stabilize the negative charge on the Lewis acid, leading to increased acidity as you move from BCl3 to BF3.
To find the number of moles of BH3 in 5.00 g of BH3, you first need to determine the molar mass of BH3. The molar mass of BH3 is 11.83 g/mol. Next, divide the given mass by the molar mass to find the number of moles. Therefore, in 5.00 g of BH3, there are 5.00 g / 11.83 g/mol ≈ 0.423 moles of BH3.
it is BH3
because ch4 has an octett and bh3 not so it dimerises to b2h6
BH3 has a bond angle of 120 degrees.
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
The BH3-THF reaction with carboxylic acids involves the formation of an intermediate complex between BH3-THF and the carboxylic acid, followed by the reduction of the carboxylic acid to an alcohol.