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Pb2+ is more stable than Pb4+ because the 6s and 6p orbitals in Pb have poor shielding ability, making it energetically unfavorable for Pb to lose 4 electrons and achieve the 4+ oxidation state. The higher charge of Pb4+ leads to greater electron-electron repulsions, making it less stable than Pb2+.
What else can I help you with?
Why is lead chloride a powerful oxidizing agent?
The oxidation state 4+ is not stable in PbCl4; the reaction is:Pb4+ + 2 e---------Pb2+
Is PbO2 As-- Pb2 AsO2 oxidized or reduced?
In the reaction involving PbO2 and Pb2 AsO2, PbO2 acts as an oxidizing agent because lead (Pb) in PbO2 is in the +4 oxidation state. When it is converted to Pb2 AsO2, the lead is reduced to a lower oxidation state, typically +2. Therefore, PbO2 is reduced in this process, while Pb2 AsO2 is oxidized.
How many electrons does an atom of lead have if it is positively charged?
Lead forms the Pb2+ ion, as lead has an atomic number of 82, the Pb2+ ion has 80 electrons in total
What is the correct cell notation for the redox reaction 3Pb2 plus aq plus 2Cr s 3Pb s plus 2Cr3 plus aq?
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
What is the chem name for pb2 po42?
The chemical name for Pb3(PO4)2 is lead(II) phosphate. This compound is formed by the combination of lead ions (Pb2+) and phosphate ions (PO43-).
How many electrons in pb2 plus?
Pb2+ has lost two electrons, so it has 82 - 2 = 80 electrons.
The reaction pbbr2s pb2 plus aq plus 2br-aq has reached saturation with concentrations pb2 plus equals 2.5 x 10-3 and br- equals 5.0 x 10-2 what is the value of ksp for pbbr2 at this temperatur?
6.3 x 10-6
Why is lead chloride a powerful oxidizing agent?
The oxidation state 4+ is not stable in PbCl4; the reaction is:Pb4+ + 2 e---------Pb2+
Does Pb2 plus react with oxygen?
Yes, Pb2+ (lead ions) can react with oxygen to form lead oxide (PbO) or other lead compounds depending on the conditions.
The pb k-egde xanes data reveals that pb is in a mixed valence state of pb4 plus and pb2 plus however in literature pb is claimed to be in pb2 plus state the pb 6s2 electrons hybridize with the o 2p?
The Pb K-egde Xanes data reveals that Pb is in a mixed valence state of Pb4+ and Pb2+. However in literature Pb is claimed to be in Pb2+ state. The Pb 6s2 electrons hybridize with the O 2p electrons to form strong covalent bonding which results in the relative displacement of Pb cage with respect to the O-octahedron. This results in increase ferroelectric properties of PbTiO3.However the question is that in the covalent state of the Pb2+ will it appear as Pb4+ state in the Pb K-edge? The reason argued here is that the Pb will lose the 6s2 electrons to form the bond and hence appear to be Pb4+. Hence the argument placed by this pool of thought is from the EXAFS data what appears to be Pb4+ is actually the covalently bonded Pb2+ while what appears to be Pb2+ is actually the ionic type Pb2+.What is the oxidation state of Pb and Ti in PbTiO3 ?
What is the name for Pb2 plus and O2-?
Lead (IV) ion
What is the formula for plumbous ion?
Formula: Pb2+
What is the symbol for lead ion?
The symbol for the lead ion with a charge of +2 is Pb2+.
Pb2 plus yields Pb4 plus is this oxidation or reduction?
This is oxidation. The Pb ion is going from a +2 oxidation state to a +4 oxidation state, which means it is losing electrons and being oxidized.
Is PbO2 As-- Pb2 AsO2 oxidized or reduced?
In the reaction involving PbO2 and Pb2 AsO2, PbO2 acts as an oxidizing agent because lead (Pb) in PbO2 is in the +4 oxidation state. When it is converted to Pb2 AsO2, the lead is reduced to a lower oxidation state, typically +2. Therefore, PbO2 is reduced in this process, while Pb2 AsO2 is oxidized.
PbBr2 soluble in water?
It is very slightly soluble in water.In a saturated solution:[Pb2+] = 1.2x10-2 mol/L[Br-] = 2.4x10-2 mol/Lbecause [Pb2+]*[Br-]2 = Ks = 6.3*10-6 and [Br-] = 2*[Pb2+]
What is mean by PBM in mass transfer?
It is the log mean value of the inert B in counterdiffusion usually used to find a flux. P = pA1 + pB1 = pA2 + pB2 thus, pB1 = P - pA1, and pB2 = P - pA2, so: pBM = [pB2 - pB1]/ln(pB2/pB1) = [pA1 - pA2]/ln[(P-pA2)/(P-pA1)] happy engineering :)
