Silver has a charge of 1+ and CO3 has a charge of 2-, compounds must have charges of 0. (1+)+(1+)+(2-)=0, therefore, you get Ag2CO3. Hope this helps.
The chemical formula for Silver persulphate is Ag2(S2O8)2.
The formula for the sulfate ion is SO4^2-. The prefix "AG" may indicate silver, in which case the formula would be Ag2(SO4)2.
The molar solubility of silver oxalate can be calculated using the given Ksp value. First, calculate the solubility product (Ksp) by taking the square root of the given value, which is √(5.4x10^12) ≈ 2.3x10^6. This means the molar solubility of silver oxalate is approximately 2.3x10^-6 mol/L.
i believe 3 because Ag2 has two atoms and O only has one atom. so, 2+1=3
The equation for the formation of the dithio sulfato argentate I complex ion is: [Ag(S2O3)2]3- + 2Ag+ ⇌ [Ag2(S2O3)2]2-
Silver = Ag+1 Carbonate = CO3-2 Formula is: Ag2(CO3)
Silver = Ag+1 Carbonate = CO3-2 Formula is: Ag2(CO3)
The chemical formula for Silver persulphate is Ag2(S2O8)2.
Ag2( SO4)3
Ag is going to exist in nature as Ag2--no doubt about it. The actual reaction with carbonate is 2AgNO3 (silver nitrate) + Na2CO3 (sodium carbonate) = Ag2CO3 (silver carbonate) plus NaNO3. For some reason you get elemental silver out of this too--which you shouldn't because it's a balanced equation, but Ag2CO3 is yellowish and it's normally got gray flecks in it when you get it.
The formula for the sulfate ion is SO4^2-. The prefix "AG" may indicate silver, in which case the formula would be Ag2(SO4)2.
The chemical equation for the reaction between dilute nitric acid and aqueous silver sulfate is: 2 HNO3 + Ag2SO4 -> Ag2(NO3)2 + H2SO4
The symbol for Silver is 'Ag' not 'Na' 'Ag' is taken from its Latin name Argentinum. 'Na' is the symbol for Sodium (latin name: Natrium) Silver is an Element. Atom is the smallest unit of any substance. Two silver atom would be present in Ag2
Silver typically forms a +1 ion, known as Ag+. This is because silver is a transition metal with a single electron in its outermost shell, which it tends to lose to achieve a stable electron configuration.
Silver oxide --> silver and (+) oxygenAg2O --> Ag2 + O2BALANCED =2Ag2O --> 2Ag2 + O2
The molar solubility of silver oxalate can be calculated using the given Ksp value. First, calculate the solubility product (Ksp) by taking the square root of the given value, which is √(5.4x10^12) ≈ 2.3x10^6. This means the molar solubility of silver oxalate is approximately 2.3x10^-6 mol/L.
the chemical reaction between silver nitrate and potassium chromate in generally used in a titration to look for chloride ions , and is a two step reaction: i will give you the ionic equations, which is pretty much all you need Ag+(aq) + Cl-(s) --> AgCl(s) this part of the equation caused the solution to go cloudy. when all the chloride ions are used up then the silver reacts with the chromate ions to produce the red colour you see when the end point of the precipitation is reached: 2Ag+(aq) + CrO4 2-(aq) --> Ag2 CrO4(s) which produces the red colour the amount of silver nitrate relates directly to the chloride ion concentration as it is a 1:1 ration reaction. i hope this answers your question =)