A reagent that could not be used to separate bromine (Br) from carbon monoxide (CO) in an aqueous solution is sodium hydroxide (NaOH). This is because NaOH would not selectively react with either Br or CO, as CO is a neutral molecule and does not participate in typical acid-base reactions. Additionally, Br could form bromide ions in the solution, complicating any separation attempts. A more selective reagent would be required to achieve separation.
It is more likely to be called a precipitate.
You have to realise that a drop from the burette for instance is insignificant, if you are dealing with at least 10ml solution which you usually deal with on a titration. If you don't want to regard it as insignificant, then if NaOH is in the burette, then the solution doesn't become more concentrated with NaOH because that drop escaped.
Adding more solute to a saturated aqueous solution causes the excess solute to precipitate out of the solution as solid particles. This process is known as precipitation and helps to decrease the concentration of the solute in the solution, allowing for more solute to dissolve.
The term solution is used to indicate more than one part, a mix. Aqueous simply means relating to, similar to, containing, or dissolved in water.The last two are pertinent to your question. A solution made up of water and another liquid or water with solids dissolved in it.
Methoxyphenol is a phenol derivative and so, is soluble in water. This means that methoxyphenol will dissolve in an aqueous NaOH solution, but will not react with the NaOH.
Phenol is acidic in nature. The phenolate anion is stable through resonance. Hence, an acid base reaction ensues between phenol and NaOH in water resulting in the formation of sodium phenolate, which is highly soluble in water compared to phenol.
There are many chemicals aqueous with water, for example: Sodium Chloride (basic table salt) is. To find more check with solubility rules, if it says the the substance is soluble, then it is aqueous with water.
Yes, lactose soluble is NaOH. Sodium is Na always and is water soluble. The website Study Mode has many examples of experiments done to prove that lactose is soluble.
Aqueous titration involves using a water-based solvent for both the titrant and the analyte, while non-aqueous titration involves using a solvent other than water. Aqueous titrations are more common and are used for analyzing compounds that are soluble in water, while non-aqueous titrations are used when water may interfere with the reaction or when the compounds are not soluble in water.
No, NaOH is more soluble in water than CsOH. Sodium hydroxide (NaOH) is a strong base and dissociates completely in water, resulting in a highly soluble solution. Cesium hydroxide (CsOH) has lower solubility in water due to the larger size of the cesium ion compared to the sodium ion.
Ethanolic NaOH is used instead of aqueous NaOH in titration to avoid side reactions with water and reduce error in the titration process. The absence of water in ethanolic NaOH helps maintain the concentration and stability of the solution, resulting in more accurate and precise titration results.
yes
Benzene, being a covalent compound is not soluble in water. So a solution of benzene in water is absurd. However in answering your question I would say that, as benzene is not soluble in water it does not function as an electrolyte. Some more improvement would be that benzene itself is not an electrolyte.
An aqueous solution that contains more hydroxide ions than hydronium ions is considered to be basic or alkaline. This imbalance in ion concentration leads to a pH greater than 7. Examples of such solutions include sodium hydroxide (NaOH) and potassium hydroxide (KOH) solutions.
Yes. You can add more solute to make it more concentrated, or if some of the solvent (water) evaporates it can become more concentrated. If you add additional water, it will become less concentrated.
A reagent that could not be used to separate bromine (Br) from carbon monoxide (CO) in an aqueous solution is sodium hydroxide (NaOH). This is because NaOH would not selectively react with either Br or CO, as CO is a neutral molecule and does not participate in typical acid-base reactions. Additionally, Br could form bromide ions in the solution, complicating any separation attempts. A more selective reagent would be required to achieve separation.