Cystic Fibrosis is inherited as a recessive trait. This means that both parents have to carry the allele for the defect. Both parents are Cc which means that 25% of their children will be CC (homozyous dominant and will not be able to pass the recessive allele in subsequent generations, 50% will be Cc
(carriers) and 25% will be cc (homozygous reccessive and have Cystic Fibrosis).
Cc
50% of the offspring will have the recessive genotype (cc) for hair color when one parent is Cc and the other parent is cc. This is because all their children will inherit one "c" allele from the parent with cc genotype.
Homozygous = identical allelesHeterozygous = different allelesEven though the genotype has two of the same letter, the difference in capitalization signifies they are different.Thus, Cc is heterozygous
A person with blood genotype AC can generally marry someone with a compatible blood genotype such as AA, AC, or CC to avoid potential blood compatibility issues in offspring. It is important to consult with a healthcare provider or genetic counselor for personalized advice based on specific circumstances.
A genotype heterozygous for a gene means having two different alleles for that gene. In the case of the gene for the trait "C", a heterozygous genotype would be "Cc", with one allele coding for the trait and the other not coding for the trait.
The genotype of a person with CF is cc. The genotype of a carrier of a CF mutation is Cc.
Let's call the gene "C." Capital C means no cystic fibrosis; lower c means cystic fibrosis, since it is a recessive gene. CC is a person who does not have cystic fibrosis and also is not a carrier. Cc indicated a carrier. cc shows a person with cystic fibrosis. In order for a child to have cystic fibrosis, its parents must be: 1. cc and cc (both have cystic fibrosis, so every child will as well.) 2. Cc and Cc (both carriers; 25% chance of having a child with cystic fibrosis) 3. Cc and cc (one parent is a carrier and one has cystic fibrosis; there is a 50% chance that the children will have cystic fibrosis.)
Sure! When both parents are heterozygous carriers (Cc) for cystic fibrosis, the Punnett Square would result in a 25% chance of having a child with cystic fibrosis (cc), a 50% chance of having a child who is a carrier (Cc), and a 25% chance of having a child who is not a carrier and does not have the disease (CC).
Cystic fibrosis is a genetic disease and can only be inherited through genes. It all depends on your parents alleles. Let's say that the allele for cystic fibrosis is c. If your Mum has the allele Cc it means she is hetrozygous. If you Dad has the same allele he is also hetrozygous. When they had children, the two small c's could come together to make a child with the alleles cc. (This means that the child has cystic fibrosis and has homozygous reccessive alleles.) When they had children their alleles could also come together to make CC (homozygous dominant- this means that person doesn't carry an allele for cystic firbrosis and will never get it. This means that if that person had children with another person who has the alleles CC, their child wouldn't get it), or it could make a child with Cc alleles. The child with Cc alleles wouldn't get cystic fibrosis because the allele big C (dominant allele) over powers the allele small c (reccessive- the cystic fibrosis allele). Although this person doesn't have cystic fibrosis their children might because they carry the allele for cystic fibrosis, which is c.
No. Cystic fibrosis is an autosomal recessive disease. Each parent would have to be a carrier of a CF mutation and would be Cc.
For a baby to be born with Cystic Fibrosis, both parents must be carriers of the faulty CF gene. Where both parents carry the faulty gene, each child has a one in four chance of having CF, a two in four chance of being a carrier and a one in four chance of not having any CF genes.
Cystic fibrosis is an autosomal recessive genetic disorder, meaning that a child must inherit two copies of the mutated gene (one from each parent) to express the condition. In this scenario, both parents are likely carriers of the cystic fibrosis allele (genotype Cc), where "C" is the normal allele and "c" is the mutated allele. The older child is phenotypically normal, which could mean they are either homozygous dominant (CC) or a carrier (Cc), while the younger child inherited two copies of the mutated allele (cc) from both parents, resulting in cystic fibrosis. This cross illustrates Mendelian inheritance patterns, where two carrier parents can have a child with a recessive condition.
Cc
For a baby to be born with Cystic Fibrosis, both parents must be carriers of the faulty CF gene. Where both parents carry the faulty gene, each child has a one in four chance of having CF, a two in four chance of being a carrier and a one in four chance of not having any CF genes.
The genotype would have to be homozygous recessive if the child was completely effected by the disease. The "normal" paretns would have to have heterozygous recessive genotypes. This makes sense since the allele that causes sickle cell shows incomplete dominance when present with a normal allele in a pair. The "normal" parents actually would have a mixture of sickle cell shaped red blood cells combined with normal shaped ones. The carrier parents does not display symptoms of the disease since the regular red blood cells alone can fill the body's need for oxygen under normal circumstances. The only time the cArrier would notice would be under times of extreme oxygen demand, such as a sprint.
50% of the offspring will have the recessive genotype (cc) for hair color when one parent is Cc and the other parent is cc. This is because all their children will inherit one "c" allele from the parent with cc genotype.
Not necessarily. CC can be a homozygous genotype if both alleles are the same (for example, CC for a particular gene). However, CC can also represent a heterozygous genotype if it stands for two different alleles in a diploid organism (for example, Cc).