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Strontium(Sr) lies to the right of rubidium(Rb) in the 5th period on the Periodic Table. Ionization energy (IE) increases as you go from left to right so Sr would have a higher IE than Rb. The actual reason for this is that both of them have their valence electrons in the 5th shell, so they are the same distance from the nucleus, however, Sr has more protons in the nucleus, and thus the attraction of these electrons is greater. Greater attraction means it takes more energy to remove them.
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Why does rubidium have a larger atomic radius than lithium and iodine?
Rubidium has a larger atomic radius than lithium and iodine primarily because it is located further down the periodic table, in group 1. As you move down a group, additional electron shells are added, increasing the distance between the nucleus and the outermost electrons. Although iodine is larger than lithium, it has a higher nuclear charge, which draws its electrons closer, resulting in a smaller atomic radius compared to rubidium. Thus, the combination of more electron shells and weaker effective nuclear charge in rubidium leads to its larger atomic radius.
Who has the largest ionization energy between small non metals and large non metals?
Small nonmetals generally have larger ionization energies compared to larger nonmetals. This is because smaller atoms have their valence electrons closer to the nucleus, which leads to a stronger electrostatic attraction between the positively charged nucleus and the negatively charged electrons. As atomic size increases, the outer electrons are further away from the nucleus and less tightly held, resulting in lower ionization energies. Therefore, smaller nonmetals, like fluorine, have higher ionization energies than larger nonmetals, such as iodine.
Does an atom of fluorine have larger or smaller radius than an atom of iodine?
Smaller
How does the the energy of the iodine particles change in sublimation?
In sublimation, iodine particles transition directly from a solid state to a gaseous state, which requires an input of energy. This energy increases the kinetic energy of the iodine particles, allowing them to overcome intermolecular forces and escape into the vapor phase. As a result, the energy of the iodine particles increases during sublimation, leading to a higher degree of molecular motion in the gaseous state.
How might the size of the membrane pore compare to the size of the starch molecules?
In other words this question asks if the pores are bigger or smaller than the iodine molecules. So.... the answer is that the iodine are smaller than the pores and the pores are bigger, because the iodine molecules need room to pass through, and the pores are not selectively permeable because they let the iodine through.
Which element in each pair has the greatest ionization energy fluorine or iodine?
The ionization energy of fluorine is 1681 kJ/mol (the first) and the ionization energy of iodine is 1008,4 kJ/mol.
Why does boron have a higher ionization energy than fluorine?
Because fluorine's size is lower than that of iodine, it has a greater ionization energy than iodine. Fluorine, on the other hand, appears to have a smaller shielding effect. As a result, fluorine's nucleus attracts more valence electrons than iodine's.
What type of bond does rubidium and iodine have?
Rubidium and iodine form an ionic bond. Rubidium, a metal, donates an electron to iodine, a nonmetal, resulting in the transfer of electrons from rubidium to iodine to achieve stability. This forms the ionic compound rubidium iodide (RbI).
Can rubidium react with iodine?
Yes. Rubidium is an alkali metal in the sodium group. It will react with iodine to form rubidium iodide:- 2Rb+ I2 -> 2RbI
What is the empirical formula for iodine and rubidium?
The empirical formula for iodine is I2 and for rubidium is Rb.
What type of bond forms between rubidium and iodine?
A ionic bond forms between rubidium and iodine. Rubidium, a metal, donates its electron to iodine, a nonmetal, resulting in the formation of positively charged rubidium ions and negatively charged iodine ions that are then attracted to each other.
When rubidium react with iodine which compound will make?
Rubidium metal would react with iodine to make rubidium iodide , according to the equation: 2 Ru + I2 -> 2 RuI
Balanced equation for rubidium and iodine?
what is the balanced equation for Rubidium metal reacting with halogen iodine
What type of bond is formed between rubidium and iodine?
Ionic bond is formed between rubidium and iodine, where rubidium donates its electron to iodine to complete its valence shell. Rubidium becomes a positively charged ion (cation) and iodine becomes a negatively charged ion (anion), resulting in the formation of an ionic compound, rubidium iodide.
Which element has a higher electronegativity value Rubidium or Iodine?
Iodine has a higher electronegativity value than rubidium. Electronegativity increases across a period from left to right on the periodic table, so iodine, being on the right side of rubidium, has a higher electronegativity value.
Why is the lattice energy of potassium bromide more exothermic than the lattice energy of rubidium iodide?
The lattice energy of potassium bromide is more exothermic than that of rubidium iodide because potassium and bromine have smaller atomic sizes and higher charges, which leads to stronger ionic bonding in potassium bromide. Rubidium and iodine have larger atomic sizes and lower charges, resulting in weaker ionic bonding in rubidium iodide. The stronger ionic bonding in potassium bromide requires more energy to break, resulting in a more exothermic lattice energy.
What is the compound name for Rbl?
Rubidium iodine
