If you have an infinite sheet of charge, it is all you can see, in that direction. If it is (let us say) in front of you, then that is all you can see to the front, it has no visible edge, you can see nothing on the other side of it (you could see something in front of it, but that is beyond the parameters of the stated problem). No matter how close or how far away you may be, it looks exactly the same. It will never look any smaller as it recedes into the distance, unlike finite objects. Vision is also a form of electromagnetism. If we were talking about light emission, the amount of light you would receive from an infinite glowing sheet would always be the same, at any distance. So any other electromagnetic effect will work the same way.
Technically, what is happening is that as you move farther away, you get less field from the closer parts of the infinite sheet, but you are also exposed to more of the sheet, in exactly the same proportion.
increase the charge or decrease the distance from the source of the field.
Outside a charged spherical shell, the electric field behaves as if all the charge is concentrated at the center of the shell. This is known as Gauss's Law for a spherical surface, which states that the electric field at a distance r from the center of a charged spherical shell is equivalent to that of a point charge with the same total charge as the shell at the center. Therefore, the electric field outside a charged spherical shell decreases with the square of the distance from the center of the shell.
A point charge is an idealized model of a charged particle that has a negligible size compared to the distances involved in its interactions. It is characterized by its charge (positive or negative), which determines the nature of the electric field it generates. The electric field produced by a point charge radiates outward (for positive charges) or inward (for negative charges) and follows an inverse-square law, meaning the field strength decreases with the square of the distance from the charge. Additionally, a point charge does not possess any physical dimensions or shape, allowing it to simplify calculations in electrostatics.
we know that force on a charge in magnetic field F=qvbsinx q-charge v-velocity b-strenth 0f magnetic field x-angle between the motion of chage and the magnetic field as the charge is stationary so v=0 so,F=0 so charge donot fill any force on it.
Electric charge produces an electric field by just sitting there. It doesn't have to move. If it moves, it produces a magnetic field. It doesn't matter how the motion would be described.
The electric field produced by an infinite plane of charge is uniform and perpendicular to the plane.
The electric field equations for different geometries are: For a point charge: E kq/r2, where E is the electric field, k is the Coulomb's constant, q is the charge, and r is the distance from the charge. For a uniformly charged infinite line: E 2k/r, where E is the electric field, k is the Coulomb's constant, is the charge density, and r is the distance from the line. For a uniformly charged infinite plane: E /2, where E is the electric field, is the surface charge density, and is the permittivity of free space.
This is a matter of limits. If you are measuring the electric field at a point that is a distance off of an infinite sheet of charge the direction of the electric field will be perpendicular to the sheet due to the symmetry of the situation. We can think of the radius as the distance between a point on the sheet and the normal line to the sheet that passes through the point where the electric field is being considered. If we look at the addition to the electric field from the charge on the sheet as this radius approaches infinity the component of the electric field in the direction of the net electric field will approach 0.P.S. Drawing a diagram of the situation with arrows denoting the directions of force from different parts of the sheet can be very helpful in understanding.
The strength of an electric field is influenced by two factors: the magnitude of the charge creating the field, and the distance from the charge at which the field is being measured. The larger the charge and the closer the distance, the stronger the electric field will be.
distance between charged particles.
The strength of an electric field depends on the charge that causes it, and on the distance from the charge.
The intensity of an electric field is determined by the amount of charge creating the field and the distance from the charge. The closer you are to the charge, the stronger the electric field will be.
Gauss's Law can be used to determine the electric field produced by an infinite sheet of charge by considering a Gaussian surface that encloses the sheet. The electric field is found to be uniform and perpendicular to the sheet, with a magnitude proportional to the surface charge density.
The strength of an electric field increases as the distance from a charge decreases. This relationship follows an inverse square law, meaning that the electric field strength is proportional to 1/r^2, where r is the distance from the charge.
The strength of an electric field is influenced by the magnitude of the charge creating the field and the distance from the charge. The field strength decreases with distance from the charge following the inverse square law. Additionally, the medium through which the field is propagating can also affect its strength.
The strength of an electric field depends on the magnitude of the charge creating the field and how far you are from that charge. It is also influenced by the medium through which the field is passing.
The electric field around an electric charge is a vector field that exerts a force on other charges placed in the field. The strength of the electric field decreases with distance from the charge following the inverse square law. The direction of the electric field is radially outward from a positive charge and radially inward toward a negative charge.