All metals combine to form ionic compounds.Group 1(except hydrogen),2-12, all elements form ionic compounds.then Group 13 (except Boron), Group 14-tin and lead and Group 15 Bismuth only.The above mentioned group elements form ionic compounds.
An element in group 1, such as sodium, will want to "hook up" with an element in group 17 (halogens) to form an ionic bond, gain a full outer shell, and become unreactive. Sodium will transfer an electron to the halogen to achieve a stable electron configuration.
The largest element in a Period (row) will be on the right of that Period (i.e. an inert gas). The largest element in a Group (column) will be at the bottom of that group. Examples; Helium is larger than Hydrogen (Period 1) Krypton is larger than Potassium (Period 3) Francium is larger than Lithium (Group 1) Ununquadium is larger than Carbon (Group 3)
lithium is the third element. It is placed in group-1
Astatine is in the group 7A of the periodic table. The members of this group all have an ionic charge of -1, so At (astatine) will have a -1 ionic charge.
In general, when an element in group 1 or group 2 combines with elements in group 16 or group 17, ionic bonds are formed between the two elements.
The ionic compound for sodium nitride is Na3N. Sodium (Na) is a group 1 element with a +1 charge, while nitrogen (N) is a group 15 element with a -3 charge. The compound is formed by combining these ions in a 3:1 ratio to balance the charges.
The formula for the ionic compound formed between rubidium and sulfur is Rb2S. Rubidium is a group 1 element with a +1 charge, and sulfur is a group 16 element with a -2 charge. To balance the charges, two rubidium atoms are needed for every sulfur atom.
Assuming you are using "Group IA1" to refer to the alkali metals (Li, Na, K, Rb, Cs, and Fr) the most probable ionic charge would be 1+. These metals have a single valence electron (when neutral) that is "lost" to a nonmetal during the formation of an ionic bond.
All metals combine to form ionic compounds.Group 1(except hydrogen),2-12, all elements form ionic compounds.then Group 13 (except Boron), Group 14-tin and lead and Group 15 Bismuth only.The above mentioned group elements form ionic compounds.
The ionic charge depends on the number of valence electrons. Alkali metals, alkaline earth metals and aluminium have 1, 2 and 3 valence electrons respectively and will hence form ions with +1, +2 and +3 charges respectively.
The formula for the ionic compound formed between strontium (Sr) and tellurium (Te) is SrTe. Strontium is a group 2 element, providing a 2+ cation, while tellurium is a group 16 element, providing a 2- anion. The compound is neutral and balanced with a 1:1 ratio of Sr to Te.
The correct formula for the ionic compound formed between sodium and sulfur is Na2S. Sodium is a group 1 element with a +1 charge, and sulfur is a group 16 element with a -2 charge. Therefore, two sodium atoms are needed to balance the charge of one sulfur atom.
The formula for the ionic compound formed between strontium (Sr) and sulfur (S) is SrS. Strontium is a group 2 element with a 2+ charge, while sulfur is a group 16 element with a 2- charge. Therefore, they combine in a 1:1 ratio to form a neutral compound.
An element in group 1, such as sodium, will want to "hook up" with an element in group 17 (halogens) to form an ionic bond, gain a full outer shell, and become unreactive. Sodium will transfer an electron to the halogen to achieve a stable electron configuration.
The bonding will likely involve ionic bonding between a Group 5 element from Period 3 and a Group 7 element from Period 2. Group 5 elements typically form 3- ions, while Group 7 elements typically form 1- ions. The attraction between these ions would result in the formation of an ionic compound.
In general, when an element in group 1 or group 2 combines with elements in group 16 or group 17, ionic bonds are formed between the two elements.