Absolute temperature was introduced to resolve this problem.
If 25 Kelvin is doubled to 50 Kelvin then average kinetic energy and hotness also doubles.
Consider an example:
Suppose the temperature is 0 Celsius at midnight. At noon it will be twice as hot.
This is a paradox because mathematically it will be the same. (2x0=0)
The same is true for the question at hand.
25 degrees Celsius is the same as 298 Kelvin and 50 degree Celsius the same as 323 Kelvin.
323 is not twice of 298.
The long version:Lets start with the facts. Celsius is a scale of measuring temperature. It is a common scale that is used most all over the world, even in US, although they are more used to Fahrenheit.To say that 50 degrees Celsius is twice as hot as 25 degrees Celsius makes sense. 25x2 equals 50.
The math does not lie. Math can not lie. This is true to the scale applied.
From this I could say that the statement made in the question regarding this is incorrect, you must be wrong.
However.
If I am assuming that you are correct in your statement, then there "must" be an "error" somewhere.
We know that the Celsius scale is a relative scale but where does it begin? Where are the "end-points"?
We know that it has got negative values as well. How far down does it go?
Lets consider 1 Degree Celsius as One unit of measurement.
Celsius goes down to -273 Degrees Celsius. This makes 273 units before its relative start point of Zero. This is where we now "invert" the Celsius scale and start at the very bottom and only deal with positive numbers.
We have now "re-invented" the Absolute Scale of Kelvin. The units are the same. One Kelvin unit is equal to One Celsius Unit. It starts at the beginning instead of "way up".
We will now think about the question using this absolute Kelvin scale instead.
First we convert 25 and 50 into Kelvin (we just add 273 to both. This works because the units are the same.) This gives 298 K and 323 K.
Kelvin gives us the actual energy level (as in heat) instead of an energy level related to the melting point of ice as Celsius does. From this we can see that 323 k is not the double of 298 k and your statement in the question is correct.
I will again point out that Math does not lie.
Note.
Math can easily be "deceiving" when one need one kind of an answer and ask the question in regards to something else.
Some questions does only make sense when thinking about them "outside the box".
Scientists think "outside the box" all the time. :-)
The temperature must decrease by 275 degrees Celsius to reach the freezing point of helium at -272 degrees Celsius.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
how many moles are contained in 4.67 L sample of gas at 33 degrees celcius and 199 kpa
The mass of the helium gas sample is already given as 4.00 grams. This value represents the weight of the gas under the specified conditions of temperature and pressure. Therefore, the mass of the sample is 4.00 grams.
When the temperature of a sample of water is -5 degrees Celsius, the water is in a solid state, as it is below the freezing point of water at 0 degrees Celsius. At this temperature, water molecules have slowed down and formed a crystalline structure, resulting in the solid state known as ice.
The temperature must decrease by 275 degrees Celsius to reach the freezing point of helium at -272 degrees Celsius.
When the temperature of a sample of water is -5 degrees Celsius, the water is frozen and in a solid state.
No, a sample of water will expand and increase in volume when warmed by several degrees Celsius due to thermal expansion.
The answer is 20 times 75.
The temperature difference in Kelvin is the same as in Celsius. So, if the sample rises by 12 degrees Celsius, it also rises by 12 Kelvin.
When a sample of water is heated past 100 degrees Celsius, it is past its boiling point. At this temperature, water changes from a liquid to a gas.
The temperature of a urine sample should be around 98.6 degrees Fahrenheit (37 degrees Celsius) to be considered valid.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
The sample of water that contains the most heat energy is the 20 g sample at 10 degrees Celsius because it has double the mass of the 10 g sample. Heat energy is directly proportional to mass, so the sample with more mass will contain more heat energy.
The temperature of the water is 100 degrees celsius.
how many moles are contained in 4.67 L sample of gas at 33 degrees celcius and 199 kpa
To calculate the amount of ice water needed to cool the sample to 20 degrees Celsius, you would need the initial temperature of the sample, the mass of the sample, and the specific heat capacities of water and ice. With this information, you could use the equation q = m * c * ΔT to determine the quantity of ice water needed to cool the sample.