answersLogoWhite

0

In the electron configuration of an atom, the 4s orbital is generally filled before the 3d orbital due to the lower energy level of the 4s orbital. This follows the Aufbau principle, where electrons fill orbitals in order of increasing energy. Thus, in the electron configuration of an atom, the 4s orbital is filled before the 3d orbital, leading to the configuration 4s2 instead of 3d2.

User Avatar

AnswerBot

1y ago

What else can I help you with?

Related Questions

What is the electron configuration for Ti (titanium)?

[Ar]4s23d2


What is the noble gas configuration for Ti?

The noble gas configuration for Titanium (Ti) is [Ar] 3d2 4s2.


What is the ground state electron confuguration for titanium?

maybe you should put this question on wiki answers.com cause they have alot of intelegent people to answer these sorts of questions


What is the period for the element represented by this electronic configuration Ar 4s2 3d2?

The element is titanium and is in 4th period, group 4.


What is the noble gas configuration of titanium?

[Ar] 3d2 4s2


What is electron configuration for Ti?

Titanium --------------------------> Ti4+ + 4e-[1s2, 2s22p6, 3s23p6] 3d2, 4s2 --->[1s2, 2s22p6, 3s23p6] + 4 electrons (from 3d and 4s orbital)Ti4+ is iso-electronic to Argon [1s2, 2s22p6, 3s23p6 ], the foregoing noble gas.


What is the correct electron configuration for Ti titanium?

[Ar]4s23d2


The electronic configuration of element in period 3 group 4 of the periodic table is?

Period 4, Group 14 (= IV-A)Germanium, 32Ge, [Ar] 3d10 4s2 4p2 KLMN: (2, 8, 18, 4)Period 4, Group 4 (= IV) Titanium, 22Ti, [Ar] 3d2 4s2 KLMN: (2, 8, 10, 2)


What are the correct electron configuration for vanadium?

1s2 2s2 2p6 3s2 3p6 4s2 3d3A+


How many core electrons does titanium have?

Titanium has 10 core electrons, which are the electrons in the inner energy levels that are not involved in chemical bonding. The electron configuration of titanium is 1s2 2s2 2p6 3s2 3p6 4s2 3d2.


What is the spectroscopic notation for the vanadium ion?

1s2 2s2 2p6 3s2 3p6 4s2 3d3


How do you solve 3d2 20d 12?

If you mean: 3d2+20d+12 then it is (3d+2)(d+6) when factored with the help of the quadratic equation formula