because it does
In KCIO2, the overall charge of the compound is zero because potassium (K) has a +1 charge, oxygen (O) has a -2 charge, and the sum of the oxidation states must equal zero. Therefore, the oxidation state of chlorine (Cl) in KCIO2 is +5.
The oxidation state of oxygen in O2PtF6 is zero. In a molecule of O2, the oxidation state of each oxygen atom is -2. Additionally, the compound PtF6 has a +6 charge, so the two oxygen atoms in O2PtF6 must have an oxidation state of zero to balance the overall charge of the compound.
A pure metal has the oxidation state zero.
O = -2 oxidation state H = +1 oxidation state
zero (0)
No, the oxidation number of carbon in C6H12O6 is +4. Each of the six carbon atoms in glucose has an oxidation state of +4 because they are bonded to more electronegative elements (oxygen and hydrogen) which pulls electron density away from carbon.
Graphite is pure carbon.So it has 0 oxidation state.
The oxidation state of carbon in formaldehyde (CH2O) is +2. This is because oxygen typically has an oxidation state of -2, and there are only two atoms of oxygen present in formaldehyde. The overall charge of formaldehyde is zero, so the sum of the oxidation states must equal zero, leading to carbon having an oxidation state of +2.
In KNO3, the oxidation state of the carbon atom is +4. In nitrate (NO3-), the overall charge is -1, and the oxygen atoms have an oxidation state of -2. Since there are three oxygen atoms bonded to the carbon atom, the carbon atom must have an oxidation state of +4 to balance out the charges.
The oxidation number of carbon in carbon dioxide (CO2) is +4. This is because oxygen typically has an oxidation number of -2, and since there are two oxygen atoms bonded to the carbon atom in CO2, the carbon atom must have an oxidation number of +4 to balance the charge.
To calculate the oxidation number of carbon in C3H8O6, we need to consider the oxidation states of the elements involved. Here's the step-by-step calculation for the carbon atom: Hydrogen (H) always has an oxidation state of +1. Oxygen (O) typically has an oxidation state of -2. The overall molecule is neutral, so the sum of the oxidation numbers equals zero. Using the molecular formula C3H8O6, we can set up an equation to solve for the oxidation number of carbon (C), keeping in mind the known oxidation states of H and O. By applying these principles, you can determine the oxidation number of carbon in C3H8O6.
all the pure elements have zero oxidation state.....
The oxidation number of Iodine (I) in HIO2 is +3. This is because the sum of the oxidation numbers in a neutral molecule must add up to zero, and since hydrogen is typically assigned an oxidation number of +1, and oxygen is typically assigned an oxidation number of -2, the oxidation number of Iodine is +3.
Beans
Here O S of C is -4As,let us take O S of C as xSo, O S of H is +1In CH4 as it is stable so the eq. isx+4(+1)=0or, x = - 4
Zero.for an element in the free state oxidation no is always zero.
all the pure elements have zero oxidation state.....