Br2 + C2H4 → C2H4Br2 OR
Br2 + CH2=CH2 → BrCH2CH2Br
The name of the reaction is pretty intuitive. Ethene's double bond is broken which leaves room for bromine to be added to form dibromoethane.
The addition product formed by ethene and water is ethanol. This reaction involves the addition of a water molecule across the carbon-carbon double bond in ethene, resulting in the formation of ethanol.
Compounds with multiple bonds, such as alkenes and alkynes, typically take part in addition reactions. In these reactions, the multiple bond is broken and new atoms or groups are added to the molecule.
The question is not very specific, so there is more than just one answer, but I'm assuming you are referring to a radical bromination of an alkane (ethane) versus an electrophilic bromination of an alkene (ethene).Br2 in the presence of a radical initiator (such as light or heat) will add to ethane to form 2-bromoethane as the major product in a radical mechanism. This goes through an initiation step (forming 2 bromine radicals), followed by propagation to the alkane (forming a secondary ethyl radical), followed by a termination step. The termination step leading to the product is one where another bromine radical joins with the ethyl radical.In the absence of light or heat, bromine cannot react with an alkane, but it can react as an electrophile with an alkene. In this type of reaction (electrophilic addition to an alkene), the ∏-bond (double bond) on ethene attacks a bromine atom (from Br2) and kicks out a bromide (Br-). The bromine that was just added forms two bonds (one on each carbon of the double bond), giving a three-membered C-Br-C ring called a bromonium ion (since the bromine atom now has a positive charge). The bromide that left before can now attack the backside of the bromonium ion, opening the 3-membered ring, and adding anti to form a dibromoalkane (1,2-dibromoethane in this example). This reaction is stereospecific because in the major product the bromine atoms will always add anti (to the opposite side) on the alkene.
You are trying to reduce ethane to ethene, I am guessing. That is a very hard reaction to do... probably you will have to do a free radical halogenation on ethane to form 1-chloroethane, followed by an E2 reaction with t-butoxide or some other bulky base to form ethene. Since ethane and ethene are both gases and cheaply available from petroleum cracking, this reaction really isn't worth doing.
yes, because the hydration of ethene or ethylene (C2H4) is process of reacting ethene with water(H2O) which gives out ethanol. for more information please visit wikipedia regards~anonymous
The reaction of ethene with bromine is called an addition reaction because the bromine atoms add across the double bond of ethene to form a single product molecule. The double bond in ethene breaks and new single bonds are formed with bromine, resulting in an overall increase in the number of atoms in the product compared to the reactants. This type of reaction is characteristic of addition reactions where atoms or groups are added to a double or triple bond.
Br2 + C2H4 → C2H4Br2 ORBr2 + CH2=CH2 → BrCH2CH2BrThe name of the reaction is pretty intuitive. Ethene's double bond is broken which leaves room for bromine to be added to form dibromoethane.
If ethene is shaken with bromine water, the orange color of bromine water will be decolorized due to the addition reaction of bromine to ethene. This reaction results in the formation of a colorless compound called 1,2-dibromoethane.
it goes from a browny orange to colourless
Bromine is an electrophile (electron deficient species) it attacks the Carbon doubble bond and accepts a pair of electrons. this is known as electrophillic addition. the equation is: C2H4 + Br2 - C2H4Br2 the product is 1,2 dibromoethane. this product is colourless.
Bromine water test is used to show that ethene is unsaturated. In the presence of ethene, the red-brown color of bromine water disappears due to addition reaction with ethene, indicating its unsaturation.
Yes, ethene reacts with bromine water to form a colourless solution. In the presence of ethene, the orange-brown color of bromine water disappears as bromine is consumed in the addition reaction with ethene to form a colourless compound.
Yes, however it doesn't require it either to react. ethene+bromine water→1,2-dibromoethane Ethane reacts with bromine only in the presence of UV forming bromoethane and hydrogen bromide.
When ethene reacts with bromine in an aqueous solution of sodium chloride, the bromine adds across the carbon-carbon double bond in ethene through electrophilic addition. This reaction forms a dibromoethane product. The presence of sodium chloride in the aqueous solution helps to generate hypobromous acid, which is the active bromine species that reacts with ethene. This reaction is an example of halogenation of alkenes.
When ethene is passed through bromine solution in carbon tetrachloride, the initially red-brown color of the bromine solution decolorizes due to the addition of bromine across the carbon-carbon double bond in ethene, forming a colorless 1,2-dibromoethane product.
One way to distinguish between ethene and ethyne is by performing a bromine water test. Ethene will decolorize bromine water, turning it from orange to colorless, while ethyne will not react with bromine water. This test takes advantage of the unsaturation in ethene that allows it to quickly react with bromine.
Such reactions are known as HYDRATION and are performed in presence of sulphuric acid.