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NO! a 120-277 electronic ballast requires one "hot" wire and a neutral from either a 110V or 277V supply. If you supply it with two "hot" wires from a 208 V supply, it will instantly burn up.

Yes. A ballast with a specification range of 120 volt to 277 volt will work on 208 volt. These ballast use intelligent voltage sensing technology and it does not matter if the source is a hot and neutral or two (2) hots. Don't believe it? Call a ballast manufacturer instead of giving incorrect answers.

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What is a 277 volt fluorescent fixture?

A 277 volt lighting fixture is one that is usually used in an industrial application. The reason for this is the voltage rating. A voltage potential of 277 volts is the voltage to neutral (ground) of a three phase four wire 480 volt distribution system. 480 volts / 1.73 = 277 volts. Rather than having to add a transformer to the system to provide 120 volts for lighting, manufactures produced a ballast for fluorescent fixtures that operates on the 227 volt potential.


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Pragmatically - YES A manufacturing company I know of has been using 277 V fluorescent ballasts on 240 V service for many years, and they are working just fine.


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1You could get 220-240V from using the two live ["hot"] wires rather than one live and one neutral. 2Tim, Industrial control transformers are available to get 120 volts from 277 volt systems. If you feed one of these with 120 volts to the secondary coil, it will put out 277 volt from the primary. However, these are rare and are not cheap. If you are trying to use surplus 277 volt fluorescent lights on a 120 volt system, it would be cheaper to replace the ballasts in the fixtures. Another approach would be to use an autotransformer with a 240 volt primary and a 32 volt secondary. If you feed it with 240 volt and wire it to boost +32 volts that will give you 272 volt which should run the lights. But again, you are looking at $60 - $100 for one circuit of lights. 3If you have access to three phase power..... Phase to ground on a 480v 3 phase system is 277v.


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