Crenation of course.
Red blood cells would exhibit crenation in a 5.0 percent solution of glucose. This is because the solution has a higher solute concentration than the cytoplasm of red blood cells, leading to water leaving the cells causing them to shrink and exhibit crenation.
The solution of potassium chloride is used to evaluate the stray light.
When red blood cells are placed in a 1.5% saline solution, the solution is hypertonic compared to the cells. This causes water to move out of the cells through osmosis, leading to the cells shrinking and potentially undergoing crenation. Gradually, the red blood cells may lose their normal shape and functionality as a result of being in a hypotonic environment.
The volume is 0,3 mL.
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
Hemolysis
None
Red blood cells would exhibit crenation in a 5.0 percent solution of glucose. This is because the solution has a higher solute concentration than the cytoplasm of red blood cells, leading to water leaving the cells causing them to shrink and exhibit crenation.
2% NaCl is hypertonic to red blood cells causing them to shrink and crenate due to water moving out of the cells by osmosis. Hemolysis is likely to occur in hypotonic solutions where red blood cells swell and burst.
This is a isotonic saline solution.
The solution being an electrolyte is electrically conductive.
The solution of potassium chloride is used to evaluate the stray light.
To find the moles of sodium chloride solute in 155 grams of an 85.5% solution, first calculate the mass of sodium chloride present in the solution (mass percent x mass of solution). Then, convert the mass of sodium chloride to moles using its molar mass (58.44 g/mol). This will give you the number of moles of sodium chloride solute in the solution.
This is an isotonic saline solution; 9 g/L sodium chloride solution in water with added glucose.
The solution has a total mass of 30 + 250 = 380 g. The mass percent of calcium chloride in this solution is 100(30/380) = 7.9 %, to the justified number of significant digits.
Divide the amount of sodium chloride by the total amount (sodium chloride + water). Then multiply that by 100 to convert to percent.
Yes, Sodium Chloride 0.9% and Normal Saline are the same solution. Normal Saline is a sterile solution of 0.9% sodium chloride in water, commonly used in medical settings for hydration and to dilute medications.