None at all, silver is less rective than copper
The product of Cu + Cl2 reacting to form CuCl2 is copper(II) chloride. In this reaction, the copper (Cu) reacts with chlorine (Cl2) to form copper(II) chloride (CuCl2) as the product.
This is a condensation polymerization.
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
This is the chemical reaction for burning of propane.
NiCl2 + 2Na --> 2NaCl + Ni
The reaction between CuCl2 (copper(II) chloride) and H2S (hydrogen sulfide) is a double displacement reaction. The balanced chemical equation is: CuCl2 + H2S -> CuS + 2HCl The products formed are CuS (copper(II) sulfide) and 2HCl (hydrochloric acid).
When copper sulfate (CuSO4) reacts with hydrochloric acid (HCl), copper chloride (CuCl2) and sulfuric acid (H2SO4) are formed as products. The balanced chemical equation for this reaction is CuSO4 + 2HCl -> CuCl2 + H2SO4.
A single-replacement reaction
The reaction between copper (Cu) and hydrochloric acid (HCl) to form copper(II) chloride (CuCl2) and hydrogen gas (H2) is a single displacement reaction. This is because the copper replaces the hydrogen in HCl to form CuCl2.
In the reaction Zn + CuCl2 → ZnCl2 + Cu, CuCl2 is the oxidizing agent because it accepts electrons from Zn, causing zinc to be oxidized and copper to be reduced.CuCl2 itself gets reduced to Cu.
2HCl + Cu -> CuCl2 + H2 Assuming that it's Copper (II). CuCl2=Copper Chloride
Yes, the reaction between Zn and CuCl2 to form ZnCl2 and Cu is a redox reaction. Zinc (Zn) is oxidized to form Zn2+ ions, while copper (Cu2+) is reduced to elemental copper (Cu).
Copper hydroxide is the precipitate.
The product of Cu + Cl2 reacting to form CuCl2 is copper(II) chloride. In this reaction, the copper (Cu) reacts with chlorine (Cl2) to form copper(II) chloride (CuCl2) as the product.
CuO + 2HCL - CuCl2 + H2O
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
This is a condensation polymerization.