No, they will not because their anions are same i.e. Nitrate
The mass of lead(II) nitrate required to react with 370 g NaOH is 1 531,9 g.
monosodium glutamate, lead diacetate, potassium bitartrate, potassium chloride, magnesium sulfate, sodium chloride, uranyl nitrate, potassium phosphate, etc.
When solutions of lead(II) nitrate (Pb(NO3)2) and potassium chloride (KCl) are mixed, a precipitate of lead(II) chloride (PbCl2) will form. This is because lead(II) chloride is insoluble in water and will precipitate out of the solution.
Zinc is more reactive than Lead nitrate (See Displacement Series). Therefore, Zinc will displace lead in lead nitrate: Zn + Pb(NO3)2 -> Zn(NO3)2 + Pb
When lead (II) nitrate is mixed with sulfuric acid (H2SO4), a white precipitate of lead sulfate (PbSO4) is formed along with nitric acid as a byproduct. This reaction is a double displacement reaction where the lead ions from the nitrate salt react with sulfate ions from sulfuric acid to form the insoluble lead sulfate.
Anything with lead ions and anything with chloride ions. So, for example, lead nitrate and sodium chloride. Getting lead into solution is actually the tricky part here; most lead compounds are not particularly soluble.
Lead can react with salts containing chloride, sulfate, and nitrate ions to form lead chloride, lead sulfate, and lead nitrate, respectively. These reactions typically result in insoluble lead compounds that may precipitate out of solution.
Lead can react with chloride salts to form insoluble lead chloride (PbCl2), such as in the reaction with hydrochloric acid (HCl) to form lead(II) chloride (PbCl2). Lead can also react with sulfate salts to form insoluble lead sulfate (PbSO4), as in the reaction with sulfuric acid (H2SO4) to form lead(II) sulfate (PbSO4).
You can separate lead nitrate from a lead nitrate solution by adding a soluble salt like sodium chloride, which will cause lead chloride to precipitate out as a solid. The lead chloride can then be filtered out from the solution, leaving you with the lead nitrate solution separated from the lead chloride.
The reaction is: 2 NaCl + Pb(NO3)2 = 2 NaNO3 + PbCl2 The lead (II) chloride is a precipitate insoluble in water.
A white precipitate, lead (II) chloride, and aqueous sodium nitrate would form. The chemical equation is Pb(NO3)2(aq) + 2NaCl(aq) --> 2NaNO3(aq) + PbCl2(s). This type of reaction is called a double replacement or double displacement.
The products of the reaction between lead(II) nitrate and sodium chloride are lead(II) chloride and sodium nitrate, which are both soluble in water. This reaction forms a white precipitate of lead(II) chloride.
These compounds doesn't react.
NO. Platinum will not react with lead(II) nitrate because platinum is BELOW lead in the activity series.
Nickel and zinc chloride: Nickel chloride and zinc Chlorine and sodium: Sodium chloride Potassium nitrate and lead iodide: Potassium iodide and lead nitrate
NO. Platinum will not react with lead(II) nitrate because platinum is BELOW lead in the activity series.
no