According to all the laws of optics, no, but there's more to it. If the mirror is of
relatively low quality, especially if the reflecting coating is on the back and the
light has to pass through the glass twice when it bounces, then the focal length
may be slightly different for different wavelengths. The result is that you see
thin borders of color around objects when you look at them in the mirror. This
is considered a cheapo mirror with a severe fault. It might be OK to shave with,
but it would never be used in an optical system like a telescope.
No, the wavelength of a sound does not change when the intensity or loudness of the sound increases. The wavelength of a sound wave depends on the frequency of the sound, which is determined by the source of the sound.
If the pitch of a sound is increased, the frequency of the sound waves also increases. Since the speed of sound remains constant in a given medium, an increase in frequency results in a decrease in wavelength. Thus, a higher pitch corresponds to a shorter wavelength.
Velocity increases when sound waves travel from gas medium to solid medium. As velocity = frequency * wave length and the frequency does not change, v is directly proportional to the wave length... Hence the wavelength increases.
The wavelength of the x-ray is shorter.
If the box is elongated, the pitch of the sound decreases. This is because the elongation increases the length of the vibrating medium, resulting in a longer wavelength and lower frequency, which is perceived as a lower pitch.
The speed of sound depends on the medium the waves pass through, and is a fundamental property of the material. It itself cannot increase wave length as it is merely a property and not an active force that can modify anything.
The speed of wave energy propagation in water increases as the length of the wavelength increases.
Speed is (Length/Time). Wavelength is (Length), and Frequency is (1/Time).Speed = (Wavelength)*(Frequency). With a constant speed, Wavelength and Frequency are inversely proportional to each other. So if one increases, the other decreases.
No. the wave length decreases as the frequency of an energy wave increases and vise versa. We acyually are learning thatin my 8th grade science class.
When you increase sound, the wavelength of the sound decreases. This is because sound waves with higher frequencies have shorter wavelengths. So, as the sound becomes louder, the frequency increases and the wavelength gets shorter.
dispersion increases and wavelength decreases
No, the wavelength of a sound does not change when the intensity or loudness of the sound increases. The wavelength of a sound wave depends on the frequency of the sound, which is determined by the source of the sound.
With a water wave, an increase in the length of the wavelength will result in a decrease in the frequency of the wave. We could say that there is an inverse relationship between the frequency and the wavelength. As one increases, the other decreases, and as one decreases, the other increases.
For electromagnetic radiation,c = speed of light = 3.0 x 108 m/s = frequency x wavelengthAs the frequency of light waves increase, the wavelength decreases. For electromagnetic radiation, the wavelength times the frequency equals the speed of light, c, which is 3.0 x 108 m/s. So, if the frequency increases, the wavelength will decrease, and if the wavelength increases, the frequency decreases.
Frequency is inversely proportional to the wave length, thus saying the shorter the wave length the higher the frequency and vice versa.The frequency is the number of waves within a time period. As the frequency within that time period increases, the number of waves increases, therefore the width of each wave (wavelength) within that time period has to decrease. Therefore:As the wave length increases, the frequency decreasesAs the wave length decreases, the frequency increases
It goes down. Wavelength is inversely proportional to the frequency
Wavelength shortens as frequendcy increases.